We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.
Answer:
D
Step-by-step explanation:
We have the expression

First we need to distribute the negative throughout the parenthesis. Then we can combine like terms in order to simplify this expression

This answer matches D.
Answer:
13 or B
Step-by-step explanation:
1 pound=16 oz
4 1/4=4.25, 4.25*16=68
68+10=78
78/6=13
Do 4.98*7 5/8 and then you will have your answer its all in the question
9514 1404 393
Answer:
- zeros: t = 1, t = -1/2
- no: the domain of the function is t ≥ 0
- 8 feet
Step-by-step explanation:
The zeros are the values of t that make the factors zero.
1 -t = 0 ⇒ t = 1
8 +16t = 0 ⇒ t = -8/16 = -1/2
The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.
Only the positive zero is in the function's domain, so that is the only one that is meaningful.
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When t = 0 (at the time the ball is thrown), the function value is ...
h(0) = (1 -0)(8 +0) = 8
The ball is thrown from a height of 8 feet.