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2 years ago

I need help I would really thank whoever answers this for me

Mathematics

2 answers:

Lyrx [107]2 years ago

8 0

A.
6j - 3 for j = 4.
(6*4) - 3, 24 - 3 = 21.

b.
1/2b + 5 for b = 14
(1/2 * 14) + 5, 7 + 5 = 12

c.
8+4k for k = 3.5
8 + (3.5*4), 8 + 14 = 22

Hope this helps! You could always check these answers on a site called Math-way (without the dash.)

Mars2501 [29]2 years ago

6 0

To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22

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notsponge [240]

Answer:

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Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

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$r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x$

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#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

Hence, the Cartesian coordinates are (1.5,-2.6)

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