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kupik [55]
2 years ago
10

Detailed surveys are sent to 13,000 organizations on the Internet to determine who uses the Internet more (women or men). 1,468

responses were received. The margin of error was 2.8 percent, with a confidence level of 95%. What was the response rate for this survey
Mathematics
1 answer:
exis [7]2 years ago
6 0

Answer: 11.29%

Step-by-step explanation:

Given : The sample size : n= 13,000

The number of responses we received = 1,468

Then , the response rate for this survey is given by :-

\hat{p}=\dfrac{\text{\text{Number of response received }}}{\text{Sample size}}\\\\\Rightarrow\ \hat{p}=\dfrac{1468}{13000}=0.112923076923\approx0.1129

In percent , the response rate = 11.29\%

Hence, the response rate = 11.29%

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Which postulate or theorem, if any, could you use to show the two triangles are congruent?
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Answer:

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2 years ago
Frank's gas tank is 1/2 full. After he buys 7 gallons of gas, it is
Masteriza [31]
It's 28. here's proof 1/4 is 7, 1/2 is 14, 3/4 is 21, and 4/4 is 28.
5 0
3 years ago
Read 2 more answers
An empty cylindrical vase with a radius of 8 cm and a height of 9 cm is filled with 6 cm^3 of sand every 15 seconds. At the same
Andru [333]

General Idea:

The volume of cylinder is given by \pi r^{2} h, where r is the radius and h is the height of the cylinder.

Applying the concept:

Step 1: We need to find the volume of full cylinder with the given dimensions using the formula.

Volume of full cylinder =\pi r^{2} h=\pi* 8^{2} *9=576\pi cm^{3}

Volume of half cylinder =\frac{576\pi }{2} =288\pi cm^{3}

Step 2: Let x be the number of minutes of filling the sand.

6 cm^{3} of sand filled every 15 seconds, there are four 15 seconds in a minute.

So volume of sand filled in 1 minute= 6*4 cm^{3} = 24 cm^{3}.

8 cm^{3} of sand taken out of cylindrical vase every minute.

Net volume of sand filled in 1 minute = Volume of sand filled in the vase in one minute - Volume of sand taken out in 1 minute

Net volume of sand filled in 1 minute=24 cm^{3} - 8cm^{3}=16cm^{3}

Volume of sand filled in x minutes = 16x.

We need to set up an equation to find the number of minutes need to fill half the volume in cylindrical vase.

16x = 288\pi \\ \\ x=\frac{288\pi}{16}  \\ \\ x=18\pi \\ \\ x=57 minutes

Conclusion:

The number of minutes required for the base be half filled with sand is 57

6 0
3 years ago
write the equation in standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0).
Mashcka [7]

Standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Hyperbola is a plane curve generated by a point so moving that the difference of the distances from two fixed points is a constant.

Given,

The Vertices of the hyperbola =  (-12,0) and (12,0)

Foci = (-13,0) and (13,0)

a=12

ac=13

c=\frac{13}{12}

We know,

c=\sqrt{1+\frac{b^{2} }{a^{2} } }

c^{2}=1+\frac{b^{2} }{a^{2} }  \\(\frac{13}{12} )^{2}=1+\frac{b^{2} }{144}  \\\frac{169}{144}=1+ \frac{b^{2} }{144} \\\frac{b^{2} }{144} =\frac{25}{144}\\ b^{2}=25

The equation of the hyperbola is

\frac{x^{2} }{a^{2} }-\frac{y^{2} }{b^{2} }=1\\  \frac{x^{2} }{144 }-\frac{y^{2} }{25 }=1

Hence, the standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Learn more about hyperbola here

brainly.com/question/7098764

#SPJ4

4 0
1 year ago
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