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gayaneshka [121]
2 years ago
10

What is f(0)?

Mathematics
1 answer:
shepuryov [24]2 years ago
8 0

A function assigns the values. The correct option is C.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

For the given graph, the value of f(0) means the value of function when the value of x is 0. Thus, when the graph intersect with the x-axis is the value of f(0), therefore,the values of f(0) are -2, -1, 1, and 3 only.

Hence, the correct option is C.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

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An ancient Sicilian legend says that the barber in a remote town who can be reached only by traveling a dangerous mountain road
faust18 [17]

Answer:

No there cannot be.

Step-by-step explanation:

In explaining this question, I would like us to take into account who the barber is,

" the barber is the one who shaves all those, and those only, who do not shave themselves".

This barber cannot be in existence because who would shave him? If he should shave himself then there is a violation of the rule which says he shaves only those who do not shave themselves. If he shaves himself then he ceases to be a barber. And if he does not shave himself then he happens to be under those who must be shaved by the barber, because of what the rule says. But then he is the barber.

This lead us to a contradiction.

Neither is possible so there is no such barber.

4 0
3 years ago
What is true of every rhombus that is also true of every parallelogram?
Elena L [17]

Answer:

A rhombus has two pairs of parallel sides.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Cami drew part of a jet on the coordinate plane and then reflected what she had drawn over the y-axis to complete the drawing. I
Elina [12.6K]

Answer:

A' is (1,2)

B' is (4,-3)

C 'is (2,-6)

Step-by-step explanation:

A is (-1,2)

B is (-4,-3)

C is (-2,-6)

so the images of the points are reflected across the y axis, so the x coordinate is the opposite:

A' is (1,2)

B' is (4,-3)

C' is (2,-6)

5 0
3 years ago
Find an integer x such that 0&lt;=x&lt;527 and x^37===3 mod 527
Greeley [361]
Since 527=17\times31, we have that

x^{37}\equiv3\mod{527}\implies\begin{cases}x^{37}\equiv3\mod{17}\\x^{37}\equiv3\mod{31}\end{cases}

By Fermat's little theorem, and the fact that 37=2(17)+3=1(31)+6, we know that

x^{37}\equiv(x^2)^{17}x^3\equiv x^5\mod{17}
x^{37}\equiv(x^1)^{31}x^6\equiv x^7\mod{31}

so we have

\begin{cases}x^5\equiv3\mod{17}\\x^7\equiv3\mod{31}\end{cases}

Consider the first case. By Fermat's little theorem, we know that

x^{17}\equiv x^{16}x\equiv x\mod{17}

so if we were to raise x^5 to the nth power such that

(x^5)^n\equiv x^{5n}\equiv x\mod{17}

we would need to choose n such that 5n\equiv1\mod{16} (because 16+1\equiv1\mod{16}). We can find such an n by applying the Euclidean algorithm:

16=3(5)+1
\implies1=16-3(5)
\implies16-3(5)\equiv-3(5)\equiv1\mod{16}

which makes -3\equiv13\mod{16} the inverse of 5 modulo 16, and so n=13.

Now,

x^5\equiv3\mod{17}
\implies (x^5)^{13}\equiv x^{65}\equiv x\equiv3^{13}\equiv(3^4)^2\times3^4\times3^1\mod{17}

3^1\equiv3\mod{17}
3^4\equiv81\equiv4(17)+13\equiv13\equiv-4\mod{17}
3^8\equiv(3^4)^2\equiv(-4)^2\mod{17}
\implies3^{13}\equiv(-4)^2\times(-4)\times3\equiv(-1)\times(-4)\times3\equiv12\mod{17}

Similarly, we can look for m such that 7m\equiv1\mod{30}. Apply the Euclidean algorithm:

30=4(7)+2
7=3(2)+1
\implies1=7-3(2)=7-3(30-4(7))=13(7)-3(30)
\implies13(7)-3(30)\equiv13(7)equiv1\mod{30}

so that m=13 is also the inverse of 7 modulo 30.

And similarly,

x^7\equiv3\mod{31}[/ex] [tex]\implies (x^7)^{13}\equiv3^{13}\mod{31}

Decomposing the power of 3 in a similar fashion, we have

3^{13}\equiv(3^3)^4\times3\mod{31}

3\equiv3\mod{31}
3^3\equiv27\equiv-4\mod{31}
\implies3^{13}\equiv(-4)^4\times3\equiv256\times3\equiv(8(31)+8)\times3\equiv24\mod{31}

So we have two linear congruences,

\begin{cases}x\equiv12\mod{17}\\x\equiv24\mod{31}\end{cases}

and because \mathrm{gcd}\,(17,31)=1, we can use the Chinese remainder theorem to solve for x.

Suppose x=31+17. Then modulo 17, we have

x\equiv31\equiv14\mod{17}

but we want to obtain x\equiv12\mod{17}. So let's assume x=31y+17, so that modulo 17 this reduces to

x\equiv31y+17\equiv14y\equiv1\mod{17}

Using the Euclidean algorithm:

17=1(14)+3
14=4(3)+2
3=1(2)+1
\implies1=3-2=5(3)-14=5(17)-6(14)
\implies-6(14)\equiv11(14)\equiv1\mod{17}

we find that y=11 is the inverse of 14 modulo 17, and so multiplying by 12, we guarantee that we are left with 12 modulo 17:

x\equiv31(11)(12)+17\equiv12\mod{17}

To satisfy the second condition that x\equiv24\mod{31}, taking x modulo 31 gives

x\equiv31(11)(12)+17\equiv17\mod{31}

To get this remainder to be 24, we first multiply by the inverse of 17 modulo 31, then multiply by 24. So let's find z such that 17z\equiv1\mod{31}. Euclidean algorithm:

31=1(17)+14
17=1(14)+3

and so on - we've already done this. So z=11 is the inverse of 17 modulo 31. Now, we take

x\equiv31(11)(12)+17(11)(24)\equiv24\mod{31}

as required. This means the congruence x^{37}\equiv3\mod{527} is satisfied by

x=31(11)(12)+17(11)(24)=8580

We want 0\le x, so just subtract as many multples of 527 from 8580 until this occurs.

8580=16(527)+148\implies x=148
3 0
3 years ago
The circumference of a circular garden is 94.2 feet. What is the radius of the garden? Use 3.14 for it and do not round your ans
Contact [7]

Answer:

Use 3.14 for p and do not round your answer. The circumference of a circular garden is 128.74 feet. What is the diameter of the garden? Use 3.14

6 0
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