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Troyanec [42]
2 years ago
5

4^3 + (-2) ^4 = ? evaluate?

Mathematics
1 answer:
kirill115 [55]2 years ago
4 0

Answer:

80

Step-by-step explanation:

PEMDAS- do exponents first here, simplifying that to 64+16, add those to get 80.

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A rectangular prism measures 8 inches by 8 inches by 12 inches. What is it's surface area
Arlecino [84]
64 inches is the correct answer. To get it you need to multiply the length times the width.

(this is incorrect. Sorry for the inconvenience)
3 0
3 years ago
What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions
DanielleElmas [232]

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x =  1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

8 0
2 years ago
2. How many square yards of carpet will be needed for a 21 ft by 15 ft room?
ipn [44]

Answer:

The answer to your question is: 35 yd²

Step-by-step explanation:

To solve this problem, just find the data, the formula, substitute the values in the formula and find the result.

Data

Square yards = ?

Length = 21 ft

Width = 15 ft

Formula

Area of a rectangle = length x width

Substitution

Area of a rectangle = 21 ft x 15 ft

Area of a rectangle = 315 ft²

Area of a rectangle = square yards of carpet

Finally, convert ft² to yd²

315 ft² = 35 yd²

Result

Square yards of carpet = 35 yt²

7 0
2 years ago
What is the length of the conjugate axis?<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac
LuckyWell [14K]

Answer:

the length of the conjugate axis  is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1

Then

b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16

Finally the length of the conjugate axis is 16

5 0
2 years ago
I need someone to solve this equation
vaieri [72.5K]
I’m pretty sure it’s x=C-6
7 0
2 years ago
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