Answer:
72
Step-by-step explanation:
the answer for this question is 64-144a+108a^2-27a^3
The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer:
5
Step-by-step explanation:
To solve this problem, we need to set up a system of equations. Let x represent the larger number and y represent the smaller number.
x + y = 17
x - y = 7
We can solve this system by adding them together. The y cancels out because y + (-y) = 0. After that, we solve for x
2x = 24
x = 12 (Divide both sides by 2)
Now that we know the value of x, we can substitute it into one of our original equations to solve for y.
12 + y = 17
y = 5 (Subtract 12 from both sides)
So, the smaller number is 5.
Answer:
Descriptive
Step-by-step explanation:
Descriptive statistics uses the data that helps to analyse, describe, and elaborate data accurately. It also provides information regarding the population through graphs or tables. Four types of descriptive statistics are measures of frequency, measures of central tendency, measures of dispersion, and measures of position.
The given example in question is <u>descriptive statistics</u>.
