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3 years ago

En un juego de béisbol, un lanzador logra

Physics

1 answer:

ratelena [41]3 years ago

5 0

Answer:

E cinetica = 140.24 [J] "unidades en Joules"

Explanation:

Para poder solucionar este problema debemos tener un dato aproximado de la masa de la pelota de beisbol, ya que en el problema este dato no fue dado, realizamos una busqueda por internet y encontramos que la masa de una pelota de beisbol es de aproximadamente m = 142 [gr].

Datos iniciales:

m = masa = 0.142 [kg]

v = velocidad = 160 [km/h]

debemos convertir de kilómetros por hora a metros por segundo.

$160[\frac{km}{h} ]* 1000 [\frac{m}{1km} ]*1[\frac{h}{3600s} ]\\44.44[\frac{km}{h} ]$

Sabemos que la energia cinetica se define por medio de la siguiente ecuacion:

$E_{k}=0.5*m*v^2\\reemplazando\\\\E_{k}=0.5*0.142*(44.44)^{2}\\E_{k}=140.24[J]$

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Which is an example of current electricity

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Answer:

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Explanation:

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3 years ago

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Answer:

It will not change

Explanation:

The period of oscillation of a mass-spring system is given by

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where

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k is the spring constant

As we see from the formula, the period of oscillation does not depend on the amplitude of the motion: therefore, if we change the amplitude, the time for one oscillation will not change.

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3 years ago

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postnew [5]

I agree with Maria and disagree with Mike.
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3 years ago

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Light is shining perpendicularly on the surface of the earth with an intensity of 680 W/m^2. Assuming that all the photons in th

andrew11 [14]

Answer:

3.066×10^21 photons/(s.m^2)

Explanation:

The power per area is:

Power/A = (# of photons /t /A)×(energy / photon)

E/photons = h×c/(λ)

photons /t /A = (Power/A)×λ /(h×c)

photons /t /A = (P/A)×λ/(hc)

photons /t /A = (680)×(678×10^-9)/(6.63×10^-34)×(3×10^-8)

= 3.066×10^21

Therefore, the number of photons per second per square meter 3.066×10^21 photons/(s.m^2).

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3 years ago