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hammer [34]
2 years ago
12

1: A man standing on the South Pole of the Earth drops a ball. Mike thinks that the ball will move away from the Earth and Maria

thinks that the ball will move toward the Earth.
​
2. Who do your agree with?

3. Who do you disagree with?

What could you say to that person to convince them that their idea is not correct?

(Science Test)
Physics
1 answer:
postnew [5]2 years ago
6 0
I agree with Maria and disagree with Mike.
The earth has gravity and that pulls objects towards the center of the planet
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Help please!!! Physics circular motion
svp [43]

Answer:

2. 3.1415 m/s

3. 0.63m

4. 0.006 m/s^2

Explanation:

2. v=(2*pi*r))/T, put in values and solve.

3. Circumference=2*pi*radius, radius is 0.1m, plug in and solve.

4. a=(v^2)/r, (don't worry about converting to meters, since units are the same in kilometers, they will cancel out) plug in values and solve.

That's it!

6 0
2 years ago
Please answer i need help asap!!!
Alexus [3.1K]
The time to distance ratio is 2.1:1 , making the first time 5 seconds, the first distance 18.9 m, and the second time 15 seconds. I hope this helps!
5 0
3 years ago
What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?
makkiz [27]

Answer:1.7\times 10

Explanation:

Given

Force F=7 N

time interval t=2.5 s

Impulse is given by =Force \times time\ interval\ for\ applied\ force

Impulse=7\times 2.5=17.5

For two significant Figure

Impulse=1.7\times 10

                       

7 0
2 years ago
A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat
Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg  

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

m g =\dfrac{mv^2}{r}

9.81 =\dfrac{v^2}{0.675}

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)

where, I =\dfrac{2}{5}mr^2

\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)

0.7 u^2 + g H = 0.7 v^2 + g(2R)

0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial  speed is 3.35 m/s

8 0
2 years ago
In a crash or collision, why is it advantageous for an occupant to extend the time during which the collision is taking place?
Veseljchak [2.6K]

Answer:

Explanation:

During a car collision momentum of vehicle ceases within a fraction of seconds so Force due to the impulse is huge.

Impulse is defined as the product of average force and time. If we can increase the period of collision for the same impulse then the average force imparted will be less.

If we can increase the time period then damage due to collision will be less.

                     

3 0
2 years ago
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