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hammer [34]
2 years ago
12

1: A man standing on the South Pole of the Earth drops a ball. Mike thinks that the ball will move away from the Earth and Maria

thinks that the ball will move toward the Earth.
​
2. Who do your agree with?

3. Who do you disagree with?

What could you say to that person to convince them that their idea is not correct?

(Science Test)
Physics
1 answer:
postnew [5]2 years ago
6 0
I agree with Maria and disagree with Mike.
The earth has gravity and that pulls objects towards the center of the planet
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Free pointzzzzz for everyoneeeee
PolarNik [594]

Answer:

Thank you so much.

Explanation:

Please give me brainliest :) I will greatly appreciate it :D

7 0
2 years ago
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Americium-241 is used in smoke detectors. It undergoes alpha decay with a half life of 432 years. The alpha particles ionize som
babymother [125]

Answer:

860.6 years.

Explanation:

The parameters given are;

Initial detector activity = 370000 alpha decays per second

Final detector activity = 93000 alpha decays per second

Formula for time to change in activity is given by the following relation;

t_{93000} = \dfrac{-ln\dfrac{A}{A_0} }{\lambda} =  \dfrac{-ln\dfrac{93000}{370000} }{5.08 \times 10^{-11}} = 2.72 \times 10^{10} \, seconds

t₉₃₀₀₀ = 2.72 × 10¹⁰ seconds = 860.6 years.

3 0
3 years ago
If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 50 km/h . The c
PtichkaEL [24]

Answer:

Explanation:

v = 50 km / h

= 13.89 m /s

When a vehicle runs on a circular path , it is static friction which prevents it from getting overturned .

static friction = μs mg

centripetal force = m v² / R

m v² / R = μs mg

R = v² / μs x g

= 13.89² / .7 x 9.8

= 28.12 m .

7 0
3 years ago
Two resistors, R1 = 25.0 ohms and
Leni [432]

Answer: 0.078

Explanation:

Given variables:

R1 = 25.0 , R2 = 64.0 , I1 = 0.200

Step 1: find V

0.200 = v/25

0.200 * 25 = v

5 = v

Step 2: Solve for I2

I = V/R

I = 5/64

I = 0.078125

Hope this helps!

3 0
3 years ago
MIT’s robot cheetah can jump over obstacles 46. cm high and has speed of 12.0 km/h. a) If the robot launches itself at an angle
labwork [276]

Answer:

(a)  y_{max}=0.423m

(b)  \alpha =64.3^{o}

Explanation:

Given data

v_{i}=12km/h=3.33m/s\\\alpha =60^{o}\\g=9.8m/s^{2}\\Required\\(a)y_{max}\\(b)Angle

Solution

For Part (a)

As the velocity component in direction of y is given by:

v_{yi}=v_{i}Sin\alpha \\v_{yi}=3.33Sin60\\v_{yi}=2.88m/s

The maximum displacement is given by:

v_{yf}^{2}=v_{yi}^{2}-2gy_{max}\\ y_{max}=\frac{(2.88)^{2}}{2(9.8)}\\ y_{max}=0.423m

For Part (b)

To reach y=46cm =0.46m apply:

0=v_{yi}^{2}-2(9.8)(0.46)\\v_{yi}=3m/s\\As\\Sin\alpha =\frac{v_{yi}}{v_{i}}\\\alpha  =Sin^{-1}(\frac{v_{yi}}{v_{i}})\\\alpha =Sin^{-1}(\frac{3}{3.33} )\\\alpha =64.3^{o}

5 0
3 years ago
Read 2 more answers
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