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kari74 [83]
3 years ago
5

A mass is bobbing up and down on a spring. If you increase the amplitude of the motion, how does this affect the time for one os

cillation?
Physics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

It will not change

Explanation:

The period of oscillation of a mass-spring system is given by

T=2\pi \sqrt{\frac{m}{k}}

where

T is the period

m is the mass hanging on the spring

k is the spring constant

As we see from the formula, the period of oscillation does not depend on the amplitude of the motion: therefore, if we change the amplitude, the time for one oscillation will not change.

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The angle of elevation from a point on the ground to the top of a pyramid is 37 degrees 50​' The angle of elevation from a point
Serjik [45]

Answer:

The height of the pyramid is approximately 104 Ft. See the graphic attached.

Explanation:

First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.

Equation (1)

tan 37^{o}50'= \frac{Ph}{x} \\\\Ph=tan 37^{o}50'  x= 0.7766 x

Equation (2)

tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]

Matching (1) and (2)

0.7766 x=0.3281(x+183)\\\\(0.7766-0.3281)x=60.05\\\\x=\frac{60.05}{0.4485} =133.89ft

replacing x value in (1)

Ph=0.7766*133.89=103.9789\\Ph = 104 ft

5 0
3 years ago
What is a wavelength?
Pavel [41]

A wavelength is the distance between two identical peaks, troughs or crests in a wave. The unit of wavelength can be meters, centimeters, millimeters, nanometers and so on. 

6 0
3 years ago
A squirrel drops an acorn onto the head of an unsuspecting dog. The acorn falls 4.0\,\text m4.0m4, point, 0, start text, m, end
kirill [66]

Answer:

0.903 seconds

Explanation:

To find how many seconds the acorn fall, we can use the formula for distance travelled with constant acceleration:

D = Vo*t + a*t^2/2,

where D is the distance travelled, Vo is the inicial speed, t is the time and a is the acceleration.

In our problem:

Vo = 0,

a = g = 9.81 m/s2,

D = 4 meters.

So, we can solve the equation to find the time:

4 = 0*t +9.81*t^2/2

4.905*t^2 = 4

t^2 = 4/4.905 = 0.8155

t =   0.903 seconds

8 0
3 years ago
Assume a change at the source of sound reduces the wavelength of a sound wave in air by a factor of 3.
noname [10]

Explanation:

The speed of a wave is given by :

v=f\lambda ......(1)

(i) Here, the wavelength of a sound wave in air reduces by a factor of 3. Equation (1) becomes :

\lambda=\dfrac{v}{f}

Wavelength and frequency are inversely proportional to each other. So, if wavelength of a sound wave in air reduces by a factor of 3, then the frequency will increases by a factor of 3.

(ii) It remains the same.

8 0
3 years ago
8. List three temperature scales. Then write the boiling and freezing
Tomtit [17]

Explanation:

For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.

Three known temperature scales;

  • Kelvin scale
  • Celcius scale
  • Fahrenheit scale

                               Kelvin scale              Celcius scale          Fahrenheit scale

Freezing point             273K                            0°C                        32°F

Melting point                373K                          100°C                     212°F

5 0
2 years ago
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