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Naddik [55]
3 years ago
12

If (2,0) is a solution of the linear equation 2x+3y=k,then the value of k is​

Mathematics
2 answers:
Margarita [4]3 years ago
8 0

Answer:

k = 4

Step-by-step explanation:

Plug in the values of 2 for x and 0 for y, and solve for k.

2x + 3y = k

2(2) + 3(0) = k

4 = k

k = 4

Neko [114]3 years ago
7 0
Then k is 4 because
2x+3y=k
2(2)+3(0)=k
4=k
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Determine the value of x<br> 2.12 units<br> 2.02 units<br> 12.38 units<br> 0.49 units
Olin [163]
I believe the answer is 2.02
8 0
3 years ago
Tickets to the zoo cost $14 for adults and $10 for children. A group of 12 people went to the zoo, and the tickets cost $140. Th
hjlf
 x is the number of adults and y is the number of children.
   x + y = 12
<span>14x + 10y = 140
lets multiply the first equation by -10 and then add it to the second equation:
-10x - 10y = -120
</span>14x + 10y = <span>140
</span>-----------------------
4x + 0 = 20
x = 20/4
x = 5
then substitute in the original equation:
x + y = <span>12
</span>5 + y = <span>12
</span>y = 12 - 5
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therefore there were 5 adults and 7 children
8 0
3 years ago
Is 48 a perfect cube? Explain your reasoning.
Ksivusya [100]

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root (\sqrt[3]{..}) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate \sqrt[3]{48}, and see if the result is an integer.

\sqrt[3]{48} = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.

8 0
3 years ago
A company that offers tubing trips down a river rents tubes for a person to use and "cooler" tubes to carry food and water. A gr
mestny [16]

Answer: the group rented 11 Person tubes and 4 cooler tubes

Step-by-step explanation:

There are two types of tubes, Person tube and cooler tube.

Let P represent number of Person tubes that the group rented.

Let C represent number of Cooler tubes that the group rented.

The group spends $270 to rent a total of 15 tubes and Person tube $20 Cooler tube $12.50. Two linear equations can be derived from the above information

P + C = 15 - - - - - - - 1

20P + 12.5C = 270 - - - -- - - 2

Substituting P = 15 - C into equation 2,

It becomes

20(15-C) + 12.5C = 270

300 - 20C + 12.5C = 270

- 20C + 12.5C = 270 -300

7.5C = - 30

C = 30/7.5 = 4

P = 15 - C

P = 15 - 4 = 11

7 0
3 years ago
Compute the present value of $9,000 paid in four years using the following discount rates: 4 percent in year 1, 5 percent in yea
juin [17]

The sum would amount to $10,527.75 after the end of 4 years.

Step-by-step explanation:

The Problem pertains to compounding interest with varying rates over the years. Our approach to solve the problem would be in a chronological fashion starting with the 1st year

Principal- $ 9000  

Rate interest= 4%

Time period would be 1 year since the interest are considered for successive years.

We know the formulae- Amount= Principal (1+rate/100) ⁿ

Where “n”= time period= 1 in all cases

⇒Amount after 1st year at 4% rate= 9000(1+4/100)  

9000*104/100= $ 9360

This amount would serve as Principal for 2nd year

⇒Hence, Amount for 2nd year at 5% rate= 9360(1+5/100)

9000*105/100= $ 9828

⇒Similarly, Amount for 3rd year at 4% rate= 9828(1+4/100)

=9828*104/100= $ 10,221.12

⇒Amount for the last year at 3% rate= 10,221.12(1+3/100)

=10,221.12*103/100= $ 10527.75

Hence the present value of the amount is $ 10527.75 after the end of 4 years.

4 0
3 years ago
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