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katrin [286]
3 years ago
10

What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

Simplified base would be 3∛4

Step-by-step explanation:

Given exponential function,

f(x)=\frac{1}{4}(\sqrt[3]{108})^x

Since, in an exponential function f(x)=ab^x

b is called base.

∵ 108 = 2 × 2 × 3 × 3 × 3,

Or 108 = 4 × 3³,

\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}

\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)  ( Using \sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b} )

\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}

\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}  ( Using power of power property of exponent )

\sqrt[3]{108}=3\sqrt[3]{4}

Hence, the required simplified base would be 3∛4

i.e. SECOND option is correct.

Aleonysh [2.5K]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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A rectangular field is 50 yards wide and 100 yards long. Patrick walks diagonally across the field. How far does he walk
S_A_V [24]

Answer:

Patrick walk approximately <u>112 yards</u>.

Step-by-step explanation:

Given:

A rectangular field is 50 yards wide and 100 yards long.

Patrick walks diagonally across the field.

Now, to find the distance he walk.

Length of the field = 100 yards.

Width of the field = 50 yards.

Now, to get the diagonal distance we put formula:

Diagonal = \sqrt{length^2+width^2}

Diagonal = \sqrt{100^2+50^2}

Diagonal = \sqrt{10000+2500}

Diagonal = \sqrt{12500}

Diagonal = 111.80

Therefore, Patrick walk approximately 112 yards.

6 0
3 years ago
How do I solve these for example 3
Natasha2012 [34]
As the three longitudinal lines are parallel:

angle 4 = 5 = 6 = 82 degree (corresponding angles) = 9 = 8 = 7 = 82 degrees (vertical angles)

and

angle 11 = 180-82= 98 degrees (linear pair)

so:

angle 10 = 11 = 12 = 98 degrees (corresponding angles) = 3 = 2 = 1 = 98 degrees (vertical angles)
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hope you got it
8 0
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