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katrin [286]
3 years ago
10

What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

Simplified base would be 3∛4

Step-by-step explanation:

Given exponential function,

f(x)=\frac{1}{4}(\sqrt[3]{108})^x

Since, in an exponential function f(x)=ab^x

b is called base.

∵ 108 = 2 × 2 × 3 × 3 × 3,

Or 108 = 4 × 3³,

\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}

\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)  ( Using \sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b} )

\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}

\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}  ( Using power of power property of exponent )

\sqrt[3]{108}=3\sqrt[3]{4}

Hence, the required simplified base would be 3∛4

i.e. SECOND option is correct.

Aleonysh [2.5K]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Why does adding a 0 to the end of a decimal not change the value of the decimal?
aniked [119]

Answer:

because after decimal then value 0 dont have meaning

8 0
3 years ago
Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair
umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

<u>Maximum value occurs at 325 at the point (0, 325)</u>

<u>Step-by-step explanation:</u>

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0
3 years ago
Determine whether the statement below is true or false. <br> 7C5 = 7C2
tia_tia [17]

True

Step-by-step explanation:

I double checked it I'm positive

4 0
3 years ago
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A crew must repave a road that is 3/8 miles long. They can repave 1/48 miles per hour. How long will it take the crew to repave
Anika [276]

Answer:

Step-by-step explanation:

3/8 miles long, 1/48 miles per hour

3/8 and 1/48 can have a common denominator, so you make 3/8 into 18/48 by multiplying both the numerator and denmoinator by 6.

18/48 miles long

1/48 per hour

divide: 18/48 divided by 1/48, which turns into 18/48 x 48/1 which equals 18

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4 0
3 years ago
Calculate the partial sum S for the sequence 243,81,27,....
Llana [10]

Answer:363


Step-by-step explanation:

We have to find partial sum for the sequence 243 , 81 , 27 ..... up to 5 terms(S5 given)

The sequence actually is 3^5,3^4.,3^3.....

Therefore first 5 terms are 1) 3^5 I.e. 243

2) 3^4 I.e. 81

3) 3^3 I.e. 27

4)) 3^2 I.e. 9

5) 3^1 I.e. 3

Adding all those no. we get partial sum of first 5 no. of the sequence

So, 243 + 81 + 27 + 9 + 3

= 363

Hope it helps!!!

4 0
3 years ago
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