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katrin [286]
3 years ago
10

What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

Simplified base would be 3∛4

Step-by-step explanation:

Given exponential function,

f(x)=\frac{1}{4}(\sqrt[3]{108})^x

Since, in an exponential function f(x)=ab^x

b is called base.

∵ 108 = 2 × 2 × 3 × 3 × 3,

Or 108 = 4 × 3³,

\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}

\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)  ( Using \sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b} )

\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}

\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}  ( Using power of power property of exponent )

\sqrt[3]{108}=3\sqrt[3]{4}

Hence, the required simplified base would be 3∛4

i.e. SECOND option is correct.

Aleonysh [2.5K]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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5x-2y=-6 3x-4y = -26​
snow_tiger [21]

For this case we must solve the following system of equations:

5x-2y = -6\\3x-4y = -26

We multiply the first equation by -2:

-10x + 4y = 12

We add the new equation with the second one:

-10x + 3x + 4y-4y = 12-26

We have different signs subtracted and the sign of the major is placed:

-7x = -14\\x = \frac {-14} {- 7}\\x = 2

Now we find the value of the variable "y":

3x-4y = -26\\3 (2) -4y = -26\\6-4y = -26\\-4y = -26-6\\-4y = -32\\y = \frac {-32} {- 4}\\y = 8

Thus, the solution of the system is given by:

(x, y) :( 2,8)

Answer:

(x, y) :( 2,8)

3 0
4 years ago
I would like to know what 0.5-0.125q=(q-1)/4 equals out to.
Scrat [10]

Answer:

q = 2

Step-by-step explanation:

0.5-0.125q=(q-1)/4

At first, we have to multiply both the sides by 4.

4 × (0.5 - 0.125q) = q - 1

or, 2 - 0.5q = q - 1

now, we change the side by taking constant into the right side and the number into the left side.

2 + 1 = q + 0.5q

or, 3 = q (1 + 0.5)

or, 3 = 1.5 q

or, 1.5 q = 3

or, \frac{1.5q}{1.5} = (3 ÷ 1.5) [Dividing both the sides by 1.5]

or, q = 2

Therefore, q = 2

8 0
3 years ago
At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =
Papessa [141]

Answer:

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

y = 2 + 2e^x − 4x

y' = 0 + 2e^x - 4

Therefore,

4 = 2e^x - 4

4 = e^x

x = ln 4 = 1.39

To find the y coordinate

y = 2 + 2e^x − 4x

y = 2 + 2e^ln 4 − 4 ln 4

y = 4.45

Hence, they are parallel at point (1.39 and 4.45)

3 0
3 years ago
Solve the proportion!
Amiraneli [1.4K]

Answer: 13

Step-by-step explanation: i googled it

5 0
3 years ago
A laboratory is testing a product by heating or cooling it at different rates. The table shows the results of four tests. Drag a
Fynjy0 [20]

Answer:

See the picture

Step-by-step explanation:

The answer is attached

3 0
3 years ago
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