Find the expression you can substitute for 5x+y=10

Mr. Ortega is buying a ham. He wants to divide it into 6-ounce servings for 12 people. Write and solve a division equation to fi

galben [10]

Answer:

division equation

x/6 = 12

The size he should buy = 72 ounces

Step-by-step explanation:

Mr Ortega bought a ham. He wants to divide it into 6 ounce serving for 12 people . The division equation to find what size of ham Mr Ortega should buy is represented below.

Mr Ortega wants to share for each person 6 ounce serving for 12 people.

Let the amount of ounce he will buy = x ounces

Therefore, the division equation to find what size of hams Mr Ortega should buy will be

x/6 = 12

To find x we cross multiply

x = 12 × 6

x = 72 ounces

8 0

3 years ago

Half a number is at least 2 units from 20. write the sentence as an absolute value inequality

Anuta_ua [19.1K]

Answer:

|1/2x - 20| ≥ 2

Step-by-step explanation:

The number is half of two and at least two units away.

8 0

3 years ago

Read 2 more answers

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

12x+5=4x+37 please help with this

hammer [34]

Answer:

x = 4

Step-by-step explanation:

12x + 5 = 4x + 37, first subtract both sides by 5 and subtract both sides by 4x

8x = 32, next divide 8 from both sides

x = 4

4 0

3 years ago

Read 2 more answers

What’s the answer to this pls?

Andrews [41]

Answer:

(0, 1 x 5)

A. (0, 5) I think

Step-by-step explanation:

7 0

3 years ago