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Burka [1]
3 years ago
11

Y^2-16y+64=81 What is the value of y

Mathematics
2 answers:
hram777 [196]3 years ago
6 0
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

y= 17, -1
NeX [460]3 years ago
4 0
Y is 12 squared idk im sorry

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I have 22 apples and my friend has 31 how many is they’re all together?
juin [17]
53 apples since 22 plus 31 = 53.
4 0
4 years ago
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What is the slope in this equation y=10+3x​
Ghella [55]

Answer:

the slope is 3

Step-by-step explanation:

4 0
3 years ago
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Given that A=xy find the percentage increase in A when both X and Y increase by 10%
Lelechka [254]
A=xy
If there is 10% increase in x then,
New value of x = x + 10%of x =1.1x
similarly for y
New value of y after increase= 1.1 y
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now
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7 0
3 years ago
A(x)=|x|+3/2<br><br><br> b(x)=-|x|<br><br><br> c(x)=2|x|
NikAS [45]

Answer:

a No solutions.

b x=0

c x=0

step-by-step explanation:

7 0
3 years ago
In 1991, the moose population in a park was measured to be 1900. By 1997, the population was measured again to be 3600. If the p
LUCKY_DIMON [66]

Answer:

Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)

The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.

Step-by-step explanation:

.

8 0
3 years ago
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