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3 years ago

An adult ticket to the show costs $2 more than a student ticket. The total cost of 3 student tickets and 2 adult tickets is $39.

Mathematics

2 answers:

klemol [59]3 years ago

7 0

And adult ticket cost $9

madreJ [45]3 years ago

4 0

Answer:

An adults ticket costs $9

Step-by-step explanation:

Kids:

Adults:

So if you add 7+7+7= 21 (kids)

then do 9+9=18(adults)

Then add them together you get 39$

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Heather lives 7 / 10 mile from theschool and 2 / 5 miles from the library . How much closer does Heather live to the library tha

frez [133]

First get the same denominator 2/5=4/10 so from here do 7/10-4/10 the denominator stays the same and the numerator changes, 3/10 is the answer so Heather live 3/10 of a mile closer to the library than the school

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2 years ago

Graph a line with a y-intercept of -3 and a slope of 1/2

OleMash [197]

Answer:

Step-by-step explanation:

(0,-3), (2,-2), (4, -1), (6,0) are on the line and (6, 0) is A

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2 years ago

Will give brainliest if done properly

k0ka [10]

Answer:

$\sf \boxed{ \sf y - 3 = \dfrac{3}{2} (x - 6)}$

Explanation:

$\sf Given \ equation: y = \dfrac{3}{2} x - 5$

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept.

Here slope: 3/2 and y-intercept: -5

Parallel slope has the same tangent slope.

Pass through point (x, y) = (6, 3)

Equation:

$\sf y - y_1 = m(x - x_1)$

$\rightarrow \sf y - 3 = \dfrac{3}{2} (x - 6)$

6 0

1 year ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago

You can draw a quadrilateral with two sets of parallel lines and no right angles. true false

yuradex [85]

False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.

5 0

3 years ago

Read 2 more answers