Answer:
Amplification.
Explanation:
Social media publishing can be defined as a service that avails end users the ability to create or upload web contents in either textual, audio or video format in order to make them appealing to a target audience.
Thus, these web contents are generally accessed by end users from time to time through the use of various network-based devices. As users access these contents, they're presented with the option of sharing a particular content with several other people a number of times without any form of limitation.
Hence, the average numbers of shares a piece of content receives is known as its amplification. The higher the average numbers of shares a particular content receives, the higher the number of traffic it generates for its publisher.
<span>1. If my memory serves me well, the answer is true. Free select tool is also called lasso and it’s used to free-hand selection. You can also combine free select tool segments with polygonal segments or other shapes.
2. I think this statement is definitely “False”. As I’ve mentioned before you can combine free selection with other selection features like polygonal by using anchors.
3. I’m not 100% sure, but I guess this one is true. As far as I remember, add to selection mode lets you to add new selection to any existing areas. So I think it’s possible to add selection to the existing one.
4. I think this one is also true. But it allows you just paint it, but it’s also kinda modification. Quick Mask allows you to isolate subject and paint selected object. It helps you not to brush subject accidentally. It’s a very useful tool as for me.
5. Yes, this statement is 100% true. But it could be gray for GIMP, because the mask is coded in gray tones, but I think that black is also gray tone. Color black or gray removes part of selection, and color white adds area to existing selection.
6. According to what I’ve mentioned before this one is also true, so there’s no need for additional explanation.
7. Another tool, similar to the Lasso/Free Select tool is the B) Scissors Tool. As there was mentioned intelligent scissors tool is almost the same as lasso but more user-friendly.
8. It’s false. You must click to the first point of your selection to finish the process or you will lose your selection.
9. I think this one is true. Paths tool includes two or more line segments connected by handle points. These points are kinda anchors I guess.
10. After making a selection using the Paths Tool, I must select the the D) Selection from Path button to turn my path into a selection. You can find it in path tool options.
11. Yes, it’s true, it allows you to make complex selections with curved or straight lines. Just drag one of the anchors to curve the line. Also you can create different geometrical figures with this tool.
12. Yes this is true. But there are much more cool blur filters than only Gaussian blur. Experiment on your own.
13. You can do all of the following given above. Every layer is kinda isolated image and you can modify it however you want.
<span>
14. I’m definitely sure that this statement is true. Just find layer drop down menu and follow the instructions given in this question. It’s simple.</span></span>
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
Possible if hackers are not so intelligent.
Explanation:
Actually, hackers are intelligent
where they will change location code in different places every second. So end-user who is trying to trace it he or she has to use their intelligence to find the exact location of hackers.
Normally hackers will generate different location places and by using decipher it is possible to find the location codes.
Since hackers used encrypted message we need to decrypts the message and find it out and understand the decrypt and encrypt technology used by hackers.
It is possible to by using decipher to get uncovered locations
Answer:
I think it's C. but not a 100%
