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Charra [1.4K]
2 years ago
14

Find the median for the following set of numbers: 12, 15, 15, 16, 19, 21, 25

Mathematics
2 answers:
Hoochie [10]2 years ago
7 0

The median is the number in the middle of the data set.

There are 7 numbers, so the 4th number is the median.

(Another method is to eliminate a number on each side until you get to the middle number)

<h2>Answer:</h2>

<u>The median is </u><u>16</u><u>.</u>

I hope this helps :)

Lera25 [3.4K]2 years ago
4 0

Answer: 16

<u>Put the numbers in order</u>

12, 15, 15, 16, 19, 21, 25

Put your left pointer finger on 12 and your right pointer finger on 25. Move your left pointer finger to the right and your right pointer finger to the left. The middle number should be 16.

Therefore 16 is the median.

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Hey guys iv got one 3 tons to pounds thanks so much.
Art [367]

Answer:

3 tons = 6000 pounds

Step-by-step explanation:

1 ton is equal to 2000 pounds, so just multiply 2000 by 3 :)

Hope this helps!

5 0
2 years ago
Read 2 more answers
The length of the box is x
Romashka [77]

A polynomial that represents the volume of the Amazon box is; V(x) = x³ - 6x² + 5x

<h3>How to calculate the volume of a box</h3>
  • Length of box = x
  • Width of the box is 4 inches less than the length. Thus; width = x - 4
  • Height is said to be 1 inch less than the width. Thus; height = x - 4 - 1 = x - 5

Now, the formula for volume of a box is;

V = length × width × height

Thus;

V = x • (x - 1) • (x - 5)

V = x(x² - x - 5x + 5)

V = x(x² - 6x + 5)

V(x) = x³ - 6x² + 5x

In conclusion, the polynomial that represents the volume of the Amazon box is V(x) = x³ - 6x² + 5x

Read more on volume of a box at; brainly.com/question/15532376

3 0
2 years ago
Nestor works as a salesperson at a car dealer and earns a $25 bonus for each car that he sells. His bonus check from the past tw
AfilCa [17]

Answer:

d

Step-by-step explanation:

4 0
2 years ago
The area of a square is 169 sq. Find it's perimeter.
pav-90 [236]

Answer:13

Step-by-step explanation:

5 0
3 years ago
Nike claims that the number of miles a jogger can get a on a pair of Nike’s running shoes is higher than 1000. Moreover, Nike al
Lisa [10]

Answer:

a) There is statistical evidence showing that Nike shoues get more than 1000 miles.

b) The p-value of t=1.84 and df=149 is P=0.034.

It represents the probability of getting this sample results if the population parameters are the ones from the null hypothesis.

In this case, the low p-value shows is rare to get a sample of n=150 and mean 1015 miles, if the population mean is 1000. This is evidence that the null hypothesis is not true.

c) There is no enough evidence to claim that Nike shoes outperform Adidas shoes by 15 miles.

d) The p-value for t=0.55 and 318 df is P=0.29.

This shows that there is a probability of P=0.29 of getting samples that show this difference if the statement of the null hypothesis is true.

Step-by-step explanation:

a) We have to perform a hypothesis test with the following hypothesis:

H_0: \mu\leq 1000\\\\H_a: \mu>1000

The level of significance is 0.05.

The sample mean is 1015 and the sample standard deviation is 100.

The degrees of freedom are df = 150-1 = 149.

The t-statistic is:

t=\frac{M-\mu}{s/\sqrt{n}}=\frac{1015-1000}{100/\sqrt{150}} =\frac{15}{8.165} =1.84

The critical value for t is t=1.66. As the t-statistic is bigger than the critical t, it falls in the rejection region. The null hypothesis is rejected.

There is statistical evidence showing that Nike shoues get more than 1000 miles.

b) The p-value of t=1.84 and df=149 is P=0.034.

It represents the probability of getting this sample results if the population parameters are the ones from the null hypothesis.

In this case, the low p-value shows is rare to get a sample of n=150 and mean 1015 miles, if the population mean is 1000. This is evidence that the null hypothesis is not true.

c) In this case, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2\leq 15\\\\H_a: \mu_1-\mu_2>15

The significance level is 0.05.

The difference between sample means is:

M_d=1015-995=20

The standard deviation of the difference is:

\sigma=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}= \sqrt{\frac{100^2}{150}+\frac{50^2}{170}}= \sqrt{66.67+14.70}=9

The degrees of freedom are:

df=n_1+n_2-2=150+170-2=318

The critical value is t=1.65

The t-statistic is:

t=\frac{M_d-(\mu_1-\mu_2)}{\sigma} =\frac{20-15}{9}= \frac{5}{9}= 0.55

The value ot the t-statistic is lower than the critical value, so it lies within the acceptance region.

There is no enough evidence to claim that Nike shoes outperform Adidas shoes by 15 miles.

d) The p-value for t=0.55 and 318 df is P=0.29.

This shows that there is a probability of P=0.29 of getting samples that show this difference if the statement of the null hypothesis is true.

6 0
3 years ago
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