Question

Assume the random variable X is normally distributed with meanmu equals 50μ=50and standard deviationsigma equals 7σ=7.Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded.Upper P left parenthesis 34 less than Upper X less than 63 right parenthesisP(34

Answer 1

Answer: 0.9575465

Step-by-step explanation:

Let the random variable X is normally distributed with mean $\mu=50$ and standard deviation$\sigma=7$ .

Using the formula , $z=\dfrac{x-\mu}{\sigma}$ , we have the z-value for x= 34

$z=\dfrac{34-50}{7}\approx-2.29$

For x= 63

$z=\dfrac{63-50}{7}\approx1.86$

P-value : P(34<x<63)=P(-2.29<z<1.86)

$=P(z$

Hence, the required probability = 0.9575465