Ask question

Ask question

All categories

2 years ago

6

Just a quick math problem that I forgot how to do.

2 answers:

Hunter-Best [27]2 years ago

6 0

Answer:

16

Step-by-step explanation:

If they are parallel then the 2 angles are congruent, so

8x + 14 = 12x - 50

64 = 4x

16 = x

Firlakuza [10]2 years ago

3 0

Answer:

x = 16

Step-by-step explanation:

For the 2 lines to be parallel, then

12x - 50 and 8x + 14 would be corresponding angles and congruent , so

12x - 50 = 8x + 14 ( subtract 8x from both sides )

4x - 50 = 14 ( add 50 to both sides )

4x = 64 ( divide both sides by 4 )

x = 16

You might be interested in

I DONT KNOW WHAT IS 89090x908

never [62]

Answer:

80 893 720

Step-by-step explanation:

hope dis helps!!!!

6 0

2 years ago

Eight plus the quotient of a number and 3<br> is −2<br><br> find answer

Fed [463]

Eight plus the quotient of a number and 3 is −2

8 + (x/3) = - 2

Hope it helps

8 0

2 years ago

The average number of points a basketball team scored for

Ganezh [65]

Average is

(2x + X+6)/3=63
(2x+x+6)= 189
3x+6=189
3x=183 61

X=61
Scores for the game are: 61, 61, and 67

3 0

3 years ago

25 points!!!! HELP ANSWER!

Fantom [35]

Answer:

a) 1st and 2nd

b) 4th one

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago