A manufacturing machine has two processes. One of them is repeated 4 times and the second only once. The entire cycle can take n
o longer than 3 minutes. Which graph represents this scenario?
2 answers:
Answer:
The graph in the attached figure
Step-by-step explanation:
Let
x -----> time of the first process in minutes
y -----> time of the second process in minutes
we know that
The time of the first process multiplied by 4 (because is repeated 4 times) plus the time of the second process multiplied by 1 (because is repeated only once) must be less than or equal to 3 minutes
so
The inequality that represent this situation is
The solution of the inequality is the shaded area below the solid line
The equation of the solid line is
The y-intercept of the solid line is the point (0,3)
The x-intercept of the solid line is the point (0.75,0)
The slope of the solid line is negative m=-4
using a graphing tool
The solution is the shaded area
The graph in the attached figure
Remember that the time cannot be a negative number
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Answer:
(0, 4.5)
Step-by-step explanation:
*The equation can be put into Desmos, to find the point, but the work to prove it is here*
f(x)=c/1+Ae^-Bx
Y=C
C=18 A=3 -B=-0.1
*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*
f(0)=18/1+3e^-o.1(0)
= 18/1+3e^0
=18/1+3(1)
=18/1+3
=18/4
=4.5
x=0 y=4.5
Maximum growth rate = (x,y) --> (0, 4.5)
Hope this helps:))!!
