multiply the first equation by 2 and the second by -3:-
6x - 10y = 14 -6x - 9y = -33 Adding these 2 equations we eliminate the term in x:- -19y = -19 y = 1 Substtute y = 1 in the first equation:_ 3x - 5(1) = 7 3x = 12 x = 4
Answer is x=4,y=1 Answer
Second system of equation:-s
Here one equation is linear and the other is quadratic so we substitute fro y in the quadratic:- From second equation y = 10x - 38, so substituting:- 10x - 38 = x^2 - 4x - 17
