(7, 0) and (11, 3) HOPE THIS HELPED!! <span>( ⸝⸝•ᴗ•⸝⸝ )੭⁾⁾</span>
Answer:
Step-by-step explanation:
Use distributive property,
a*(b - c) =a*b - a*c
6(4x - 8) = 6*4x - 8*6
= 24x - 48
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
If You mean A sum to write here's one :
31+3
