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Vladimir [108]
3 years ago
13

Factorize B (A)IBG) - (7a-41² -214-72) 1483) 1716​

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
Your solution to your question would be 7a - 1967
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Yes I wanted to know what is the answer ​
jek_recluse [69]

Answer:

14 flats

5 plants

Step-by-step explanation:

First you would do 89/6 but since that doesn’t divide nicely you can do 90/6 to get 15 then subtract 1 since the original number was 89 and you would get 14

The 14 times 6 would get you 84

Then subtract 84 from 89 and you get 5 plants left over ^^

7 0
3 years ago
Change x + 2y = 6 into slope-intercept form.
mart [117]

Answer:

The slope intercept form involves solving for y, such that the equation looks like this: y = mx + b, where m is a constant representing the slope of the line, and b is a constant representing the value of the y-intercept.

Starting with the equation x+2y=6 and subtracting x from both sides gives 2y =  -x + 6.

If we then divide each term by 2, we get the final result of y = -1/2x + 3.

Here we see that the slope (m) is equal to -1/2, and the y-intercept (b) is 3.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The line x - y = 5 passes through which set (-5, 0) (0, 5) (0, -5)
s2008m [1.1K]
The line x - y = 5 passes through points (-5,0) and (0,5)
the line in slope intercept form is y = x + 5 and plug in the point to see if the equation is true.
6 0
3 years ago
Read 2 more answers
What is the complex conjugate of 13-21i?
irga5000 [103]

Answer:

To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.

As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.

Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.

Hope this helped!!... :D

Please correct me if I'm wrong!!.. :3

3 0
3 years ago
Read 2 more answers
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
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