All categories

3 years ago

What percent of 200 miles is 150 miles

Mathematics

1 answer:

Anna71 [15]3 years ago

4 0

150 miles is exactly 75% of 200 miles.
Hope that helped =)

You might be interested in

My son has the following missing number pattern to solve.

melisa1 [442]

The only complete pattern is the middle one
we see that 38-29=9
so the middle number minus the first number equals the third number
for the last row
21-1=20 so you have 1 21 20
for the first one

17- ?=37
54-17=37 54 17 37

6 0

4 years ago

Read 2 more answers

A corporate team-building event costs $13, plus an additional $6 per attendee. How many

andrew-mc [135]

Answer:

Step-by-step explanation:

The cost for n attendees will be ...

cost = 2 + 2n

We want the cost to be, at most, 26, so we have ...

26 ≥ 2 +2n

Dividing by 2 gives ...

13 ≥ 1 + n

And subtracting 1, we find the answer:

12 ≥ n

At most, there can be 12 attendees.

5 0

3 years ago

4x-5 - 2x-1

3241004551 [841]

Answer:

$\frac{5x - 8}{3}$

Step-by-step explanation:

Find the LCM of the denominators and then solve:

$\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\$

$\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\\frac{3(4x - 5) - 2x - 1}{6} \\\\\frac{12x - 15 - 2x - 1}{6}\\\\\frac{10x - 16}{6}\\\\ \frac{2(5x - 8)}{2 * 3} \\\\ \frac{5x - 8}{3}$

4 0

3 years ago

What is the value of t in the equation t+12=30 ?

masha68 [24]

<span>Simplifying X + 12 = 30
Reorder the terms: 12 + X = 30
Solving 12 + X = 30
Solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '-12' to each side of the equation. 12 + -12 + X = 30 + -12
Combine like terms: 12 + -12 = 0 0 + X = 30 + -12 X = 30 + -12
Combine like terms: 30 + -12 = 18 X = 18
Simplifying X = 18</span>

6 0

3 years ago

Read 2 more answers

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago