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Pavlova-9 [17]
2 years ago
7

There are an average of 45 buffalos for every 125 acres in the Canadian wilderness. How many buffalos are there in 150 acres?

Mathematics
1 answer:
Nikolay [14]2 years ago
8 0

Answer:

there are 54 buffalos in 150 acres

Step-by-step explanation:

1. determine the rate of buffalos per acres

45 buffalos per 125 acres =

45 / 125 =

0.36 buffalos per 1 acre

now we know the rate of buffalos per 1 acre, we can multiply it by the required amount of acres (in this case 150)

buffalos per 1 acre x total acres = total buffalos per total acres

0.36 x 150 = 54 buffalos

therefore, there are 54 buffalos per 150 acres.

hope this helps :)

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A side of the triangle below has been extended to form an exterior angle of 128° . Find the value of x.​
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The answer is the option C

graph of 3x minus 3, with discontinuity at negative 2, negative 9

Step-by-step explanation:

we have

f(x)=\frac{9x^{2}+9x-18}{3x+6}

Simplify

f(x)=9\frac{(x^{2}+x-2)}{3(x+2)}

f(x)=3\frac{(x^{2}+x-2)}{(x+2)}

Step 1

Convert to a factored form the numerator

x^{2}+x-2=0    

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+x=2

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+x+0.25=2+0.25

x^{2}+x+0.25=2.25

Rewrite as perfect squares

(x+0.5)^{2}=2.25

Square root both sides

x+0.5=(+/-)1.5

x=-0.5(+/-)1.5

x=-0.5+1.5=1

x=-0.5-1.5=-2

so

x^{2}+x-2=(x-1)(x+2)  

Step 2

Simplify the function f(x)

f(x)=3\frac{(x^{2}+x-2)}{(x+2)}=3\frac{(x-1)(x+2)}{(x+2)}

The domain of the function f(x) is all real numbers except the number x=-2

Because the denominator can not be zero

f(x)=3\frac{(x-1)(x+2)}{(x+2)}=3(x-1)=3x-3  

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f(-2)=3(-2)-3=-9

The discontinuity is at point (-2,-9)

the answer in the attached figure

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