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Marina86 [1]
3 years ago
10

Divide;11dq^4/8d^3q^4÷5d/10d^2q^3

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

Answer: 664546^74767^-6382639r575

Step-by-step explanation:

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Find an orderd pair (x,y) that is a solution to the equation 4x+y=9
Aleksandr [31]

Answer:

Below in bold.

Step-by-step explanation:

4x + y = 9

Let's put x = 0 then:

4(0) + y = 9

0 + y = 9

y = 9

So one. ordered pair that is a solution is (0, 9)

7 0
2 years ago
A square base of a pyramid has dimensions 5 yards by 5 yards. The height of one of the triangular faces is 12 yards. How can you
siniylev [52]

A square pyramid has 4 triangles and the square base.

Calculate the area of one triangle, multiply that by 4 then add the area of the base.

Area of triangle = 1/2 x base x height = 1/2 x 5 x 12 = 30 square yards.

30 x 4 = 120 square yards

Area of base = 5 x 5 = 25 square yards

Total = 120 + 25 = 145 square yards.

7 0
3 years ago
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Firlakuza [10]

Answer:

I cant see anything

Step-by-step explanation:

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6 0
3 years ago
I need the range for this.
docker41 [41]

Answer:

(-3, 3)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What are the roots of the equation x^2+6x-9=10?
Ronch [10]

Answer:

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

a=1 b=6 c=-19

As cannot be solved by completing square we will use quadratic equation

x= (-b+sqrt(b^2-4ac))/2a     and      x= (-b-sqrt(b^2-4ac))/2a

x= (-6+sqrt(6^2-4*-19))/2     and      x= (-6-sqrt(6^2-4*-19))/2

x=(-6+sqrt(36+76))/2           and      x=(-6-sqrt(36+76))/2

x=(-6+4sqrt7)/2                   and       x=(-6-4sqrt7)/2

x=(-3+2sqrt7)                       and      x=(-3-2sqrt7)

x=2.29                                 and      x= -8.29

3 0
4 years ago
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