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Oksanka [162]
3 years ago
11

Answer pls need for math tomorrow

Mathematics
1 answer:
IrinaVladis [17]3 years ago
7 0
The correct answer is D
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Is this correct pls help
Lyrx [107]

Answer:

Volume of round cake pan = volume of cylinder

Volume of a cylinder = \pi r^2h (where r is the radius and h is the height)

Radius = \dfrac12 diameter ⇒ r=\dfrac72=3.5

⇒ volume of round cake pan = \pi \times 3.5^2 \times 2=24.5\pi

= 76.97 in³ (nearest hundredth)

Volume of rectangular cake pan = volume of rectangular prism

volume of rectangular prism = wlh (where w is the width, l is the length and h is the height)

⇒ volume of rectangular cake pan = 6 x 9 x 2 = 108 in³

As 108 > 76.97, the rectangular cake pan has a larger volume

4 0
2 years ago
Solve for a side in right triangles (soh cah toa)
nevsk [136]
Cos(35) = x/6
or 6 * cos(35) = x
3 0
3 years ago
Needs answers <br> Will mark brainliest
Elden [556K]

QUESTION 1:

Required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

QUESTION 2:

Required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Step-by-step explanation:

Question 1:

if m<1 =105°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <1 is angle 5 So, m<5 = 105°

The vertical angles are also equal. so, vertical angle of <1 is <4. So, m<4 = 105°

Vertical angles of m<5 is m<8 so, m<8=105°

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

105+m<2=180

m<2=75°

Same goes for m<3 and m<4 so, m<3 = 75°

m<5 and m<6 so, m<6 = 75°

m<7 and m<8 so, m<7= 75°

So, required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

Question No 2

if m<3=80°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <3 is angle 7 So, m<7 = 80°

The vertical angles are also equal. so, vertical angle of <3 is <2. So, m<2 = 80°

The Vertical angle of <7 is <6 so, m<6= 80°.

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

m<1+80=180

m<1=100°

Same goes for m<3 and m<4 so, m<4 = 100°

m<5 and m<6 so, m<5 = 100°

m<7 and m<8 so, m<8= 100°

So, required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Keywords: Traversal of parallel lines

Learn more about traversal of parallel lines at:

  • brainly.com/question/1598227
  • brainly.com/question/3227215
  • brainly.com/question/10483199

#learnwithBrainly

3 0
3 years ago
A paint sprayer covers 2 1/2 ft of wall in 1/8 min.
Andre45 [30]
20ft/min 2 1/2 *8=20
7 0
3 years ago
Read 2 more answers
The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product
tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0
3 years ago
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