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4 years ago

An 18 oz jar of peanut butter cost $2.19. A 48 oz jar of peanut butter sells for $4.39. Which size jar is the better buy?

2 answers:

6 0

So you divide 2.19 by 18 and you get .12 so it cost 12 cents per ounce
then you divide 4.39 by 48 and you get .09 so it cost 9 cents per ounce

So it would be better idea to but the 48 ounce jar because it costs less oer ounce of peanut butter

Crazy boy [7]4 years ago

3 0

2.19/18 = 0.12167 per ounce
4.39/48 = 0.09 per ounce

the larger jar is the better buy

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Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

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1 year ago

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AVprozaik [17]

Answer:

$\sqrt{37}$ units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.

We know the formula of length of perpendicular from a point $(x_{1}, y_{1} )$ to the straight line ax + by + c = 0 is given by

$\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}$

Therefore, in our case the perpendicular distance is

$\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}$ units. (Answer)

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Alisiya [41]

Answer

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Step-by-step explanation:

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3 years ago

the perimeter of an equilateral triangle is 150cm. If the length of the altitude of the triangle is x√3cm, what is the value of

jenyasd209 [6]

Answer:

X = 25

Step-by-step explanation:

To solve this question, we'll first of all find determine the side length of the triangle from the perimeter.

Perimeter of an equilaterial triangle = 3 * s

S = side length

Perimeter = 150cm

150 = 3s

S = 150 / 3

S = 50cm

The side lengths are 50cm each since they are all equal.

To find x,

We have to divide the triangle equally into two different part.

Check the first attachment for better illustration on how the equilaterial triangle is.

Check the second attachment for better illustration on the triangle when its divided into a right angle triangle.

From the right angle triangle, we can use pythagorean theorem to solve for x

a² = b² + c²

a = 50cm

b = 25cm

c = x√(3)

50² = [x√(3)]² + 25²

2500 = x² * 3 + 625

2500 - 625 = 3x²

1875 = 3x²

X² = 1875 / 3

X² = 625

X = √(625)

X = 25

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4 years ago