To combine these terms you would add up the a's and b's.
4a+b+a is the same as 4a+a+b. Anything without a constant in front has a value of 1. You have 4a's and you need to add another a. That equals 5a's. The b is left alone since you can only add like variables.
The answer would be C) 5a +b
Answer:
6...9...
Step-by-step explanation:
I hope this helps you
-2a^2b.4.a^5.b^2
-8.(a^2+5)(b^1+2)
-8.a^7.b^3
1. Y=X-4
2. Y=X*4
3. Y=X+3
4. Y=X/6
Answer:
digits are: 0, 4, 8. The required number is: 480.
Step-by-step explanation:
→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.
→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.
→ After evaluation this equation, x=0 - this is ones digit;
→ x+4=0+4=4 - this is hundreds digit;
→ 2(x+4)=2(0+4)=8 - this is ten digit.
