Can you help me find all the seventh roots of unity? what do they look like graphed?
1 answer:
Answer:
There are seven seventh roots of unity, e2πki7 , all on the unit circle, r=1 above.
The first one is at θ=2π7=360∘7=5137 ∘ , and there are others at 4π7,6π7,8π7,10π7,12π7 and of course at 0 radians, i.e. unity itself.
How to find?
There are 4 fourth roots of unity and they are 1, i,−1 and−i
Each of the roots of unity can be found by changing the value of k k k in the expression e 2 k π i / n e^{2k\pi i/n} e2kπi/n. By Euler's formula, e 2 π i = cos ( 2 π ) + i sin ( 2 π ) = 1.
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We also know that, for every triangle, the sum of two sides must be always bigger than the third side, for any combination.
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From this, we conclude that the third side of an isosceles triangle with sides equal to 5 and 12 is equal to 12.
