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torisob [31]
3 years ago
6

Can you help me find all the seventh roots of unity? what do they look like graphed?

Mathematics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

There are seven seventh roots of unity, e2πki7 , all on the unit circle, r=1 above.

The first one is at θ=2π7=360∘7=5137 ∘ , and there are others at 4π7,6π7,8π7,10π7,12π7 and of course at 0 radians, i.e. unity itself.

How to find?

There are 4 fourth roots of unity and they are 1, i,−1 and−i

Each of the roots of unity can be found by changing the value of k k k in the expression e 2 k π i / n e^{2k\pi i/n} e2kπi/n. By Euler's formula, e 2 π i = cos ⁡ ( 2 π ) + i sin ⁡ ( 2 π ) = 1.

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Expert Answer

Step-by-step explanation:

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12 (2 -2)+32 = (x +6) +2
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Answer: x = 24

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

<u>Step 1:</u><u> </u><u><em>Remove parentheses.</em></u>

12 (2 − 2) + 32 = x + 6 + 2

<u>Step 2:</u><u> </u><u><em>Simplify 2 − 2 to 0.</em></u>

12 × 0 + 32 = x  + 6 + 2

<u>Step 3:</u><u> </u><u><em>Simplify 12 × 0 to 0.</em></u>

0 + 32 = x +  6 + 2

<u>Step 4:</u><u> </u><u><em>Simplify 0 + 32 to 32.</em></u><em> </em>

32 = x + 6 + 2

<u>Step 5:</u><u> </u>x<u><em> + 6 + 2 to </em></u>x<u><em> + 8.</em></u>

32 = x + 8

<u>Step 6:</u><u> Subtract 8 from both sides.</u>

32 − 8 = x

<u>Step 7:</u><u> Simplify 32 − 8 to 24.</u>

24 = x

<u>Step 8:</u><u> </u><u><em>Switch sides.</em></u>

x = 24

~I hope I helped you! :)~

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