Can you help me find all the seventh roots of unity? what do they look like graphed?
1 answer:
Answer:
There are seven seventh roots of unity, e2πki7 , all on the unit circle, r=1 above.
The first one is at θ=2π7=360∘7=5137 ∘ , and there are others at 4π7,6π7,8π7,10π7,12π7 and of course at 0 radians, i.e. unity itself.
How to find?
There are 4 fourth roots of unity and they are 1, i,−1 and−i
Each of the roots of unity can be found by changing the value of k k k in the expression e 2 k π i / n e^{2k\pi i/n} e2kπi/n. By Euler's formula, e 2 π i = cos ( 2 π ) + i sin ( 2 π ) = 1.
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Answers:
x = 6
Each angle is 45 degrees
The diagram is shown below
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Explanation:
Vertical angles are always congruent
Set the two expressions equal to each other and solve for x.
5x+15 = 3x+27
5x-3x = 27-15
2x = 12
x = 12/2
x = 6
As a way to check the answer, replace x with 6 in each expression. We should get the same thing on both sides
5x+15 = 3x+27
5*6+15 = 3*6+27
30+15 = 18+27
45 = 45
Each angle is 45 degrees, so the answer is confirmed.
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The diagram is shown below. There are infinitely many ways to draw out the diagram. In the version I drew, the angles aren't vertically aligned but instead they are opposite one another in this X configuration. So the vertical angles could be vertically aligned, but they don't have to be.
In short: draw an X shape and mark any two opposite angles to form the vertical angles.
