The price of the pear is $0.6
Given:
The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear.The juice cost 1.5 times as much as the pear.The sandwich costs $1.40 more than the pear.
From above statements
Juice + sandwich + pear = $3.50 -----------eq(1)
Juice = 1.5 * pear
sandwich = pear + $1.40
substitute juice and sandwich values in eq(1)
1.5 pear + pear + $1.40 + pear = $3.50
3.5 pear = $3.50 - $1.40
pear = $2.10/3.5
pear = $0.60
Hence the price of the pear is $0.6
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Let us assign variables.
Let x = egg mcmuffins
Let y = hash brown
Randy had:
2x + y = 750
Jack had
x + y = 450
Using systems of linear equation, we can get the value for x and y by elimination. Subtract the equations.
2x + y = 750
x + y = 450
--------------
x = 300
Get y
x + y = 450
300 + y = 450
y = 150.
So there are 300 calories for McMuffins and 150 calories for hash brown.
When I finished the work my product is 1,817
