(x—3)2=-18<br> solve using square root method

For a school fund raising project, Aiden and Jacob collected money in the ratio of 3.5 : 6.8. Jacob collected $115.50 more than

user100 [1]

X - the amount of money collected by Aiden
y - the amount of money collected by Jacob

Aiden and Jacob collected money in the ratio of 3.5 : 6.8.
$\frac{x}{y}=\frac{3.5}{6.8} \\
6.8x=3.5y \\
x=\frac{3.5}{6.8}y \\ x=\frac{35}{68}y$

Jacob collected $115.50 more than Aiden.
$x+115.5=y \\
x=y-115.5 \\ \\
x=x \\
\frac{35}{68}y=y-115.5 \\
\frac{35}{68}y-y=-115.5 \\
\frac{35}{68}y-\frac{68}{68}y=-115.5 \\
-\frac{33}{68}y=-115.5 \\
y=-115.5 \times (-\frac{68}{33}) \\
y=238 \\ \\
x=y-115.5=238-115.5=122.5 \\ \\
x+y=238+122.5=360.5$

The total amount of money they collected is $360.50.

6 0

4 years ago

If a translation maps ∠D onto ∠B, which of the following statements is true? triangle CAB, point E is on segment AC between poin

mrs_skeptik [129]

Answer:

The correct option is;

ΔCED ~ ΔCAB

Step-by-step explanation:

Given that the translation maps angle ∠D to angle ∠B, we have;

Angle ∠D is congruent to ∠B (Given)

Segment ED is parallel to segment AB (lines having similar angles to a common transversal)

Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)

∠C is congruent to ∠C reflexive property

Therefore, we have;

∠C ≅ ∠C

∠E ≅ ∠A

∠D ≅ ∠B

Which gives ΔCED is similar to ΔCAB (not ΔCBA)

4 0

3 years ago

The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b

ANEK [815]

Answer:

$P(\bar X$

And we can solve this using the following z score formula:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we use this formula we got:

$z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4$

So we can find this probability equivalently like this:

$P( Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(63.6,2.5)$