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algol13
3 years ago
5

A = {x | x is a positive, odd integer less than 7} -1

Mathematics
1 answer:
Lisa [10]3 years ago
3 0

Answer

(5 2) (7 3) 2 3 5 x < x - - x - The inequality is 2 x < 5x 3 -2 – 7x 5 -3 Multiply ... Find all pair of consecutive odd positive integers both of which are smaller than 10 ... Let x be the smaller of the two odd positive integers so that the other is x + 2.

Step-by-step explanation:

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Part A
Diano4ka-milaya [45]

Answer:

24 Blue beads

16 Green beads

Step-by-step explanation:

.60×40=24

.40 ×40=16

Whenever you get a percentage move the decimal two places left and multiply by the total number.

example: 2% of 20 is 2.00 of 20, so move the decimal 2 spots to the left. .002×20=.04

5 0
2 years ago
Read 2 more answers
How to find the area of each of the shaded sectors and round to the nearest hundredth
Mazyrski [523]

Answer:

1-6 you need to write the JHI DEF where the radius center point is in the middle of each shape next to 1-6 some have 2 shapes so use 6 letters there.

Step-by-step explanation:

1. Area = 72 of 360 = 20% of 716.3 =  143.26inch*2 =JHI

2.Area =  19 of 360 = 68.4% of 69.4  = 47.46km^2 =DEF

3. Area = 92 of 360 = 25.56% of 153.9 = 39.33cm^2

4. Area = 226 of 360 = 64.57% of 706.9 = 456.45ft^2

5.  Area = 74 of 360 =  20.55% of 153.9 =31.63 inch^2

6. Area = 326 of 360 = 90.56% of 1452 -137.07 = 1314.93m^2

8 0
3 years ago
Solve for x in the equation x2 – 12х+ 36 = 90
Leviafan [203]

Answer:

5

Step-by-step explanation:

90-36=54

54-24=30

5 0
3 years ago
Simplify the following equation (2^3)^-2
koban [17]
Multiply the exponents
3 * -2 = -6
It would be 2^-6
Format: a^-b = 1/a^b
1/2^6 = 1/64
The solution is 1/64
6 0
2 years ago
(s+12)+(-3s-8) equals?
finlep [7]

Answer:

-2s + 4

General Formulas and Concepts:

  • Combining like terms

Step-by-step explanation:

<u>Step 1: Define expression</u>

(s + 12) + (-3s - 8)

<u>Step 2: Simplify</u>

  1. Combine like terms (s):                    -2s + 12 - 8
  2. Combine like terms (constants):      -2s + 4
4 0
3 years ago
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