The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Answer:
Rs. 23520
Step-by-step explanation:
Given that :
At 12% profit ; sales price = 18,816
At (12 + 3)% profit ; sales price = x
Hence,
0.12 = 18,816
0.15 = x
Cross multiply ;
0.12x = 0.15 * 18816
0.12x = 2822.4
x = 2822.4 / 0.12
x = 23520
Hence, sales price for a 3% increaa in profit should be Rs. 23520
