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3 years ago

What is the equation of a line that is parallel to the line y = 5x – 1 and passes

Mathematics

1 answer:

dsp733 years ago

5 0

Answer:

y = 5x - 23

Step-by-step explanation:

Since that is ll to y = 5x - 1, slope must be same as that of y = 5y - 1.

Compare y = 5y - 1 with y = mx + c, where m is slope.

Slope of the required line = 5.

And a point lying on that line is (4,-3). Therefore,

Equation is:

=> y - (-3) = 5(x - 4)

=> y + 3 = 5x - 20

=> y = 5x - 23

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Find the missing digit for the following bank identification numbers:

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Step-by-step explanation:

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Answer:

the answer would be 38 :)

Step-by-step explanation:

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A blueprint of a barn is shown.The scale is 5 inches =8 feet. Find the actual length of the wall that is labeled 20 inches.

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2 years ago

Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r

Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

$(x',y')=(-x, y)$ , $\forall\, x, y\in \mathbb{R}$ (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

$(x',y') =(x-3,y+2)$ , $\forall \,x,y\in \mathbb{R}$ (Eq. 2)

Where:

$(x, y)$ - Original point, dimensionless.

$(x', y')$ - Transformed point, dimensionless.

If we know that $F(x,y) = (-2, 4)$ and $G(x,y) = (-2,-3)$ , then we proceed to make all needed operations:

Translation

$F''(x,y) = (-2-3,4+2)$

$F''(x,y) = (-5,6)$

$G''(x,y) = (-2-3,-3+2)$

$G''(x,y) = (-5,-1)$

Reflection

$F'(x,y) = (5, 6)$

$G'(x,y) = (5,-1)$

Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:

$F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}$

$F'G' = 7$

The length of the segment F'G' is 7.

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