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IceJOKER [234]
2 years ago
7

26.48 divided by 2 and the method

Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0

Answer:

13.24

Step-by-step explanation:

If you put it into the calculator, you get the answer. Or you could do long division, but that's difficult for no reason. You could also divide each number individually by 2, as they are all even, so that works too.

Hope this helps!

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Plz solve, free brainlest if you solve, this my little sis’s homework
faust18 [17]

Answer:

5x6=30

6x50=300

those are two lol.

3 0
3 years ago
A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
Eric works in landscaping. He charges a fee of $25 plus $15 per hour. What is the least number of hours he must work in order to
nlexa [21]

Answer:

5 hours

Step-by-step explanation:

you would so 100 minus 25 (25 is just one charge fee) which is 75 then divide 75 into 15 which is the hourly pay, and get 5 which is the hours he must work

3 0
3 years ago
Please help me The point D,E,F and G all lie on the same segment, in that order, such that ratio of DE:EF:FG is equal to 4:1:4.
kap26 [50]

Answer:

4+1+4+g=36

g=27

dg=32

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Help Please? GEOMETRY Use the word bank to help you with possible answers (there are extra options that are not to be used)
ipn [44]
Short Answers:

Answer for part A: Definition of perpendicular
Answer for part B: Right Angle Congruence Theorem
Answer for part C: Reflexive Property of Congruence
Answer for part D: Definition of Midpoint
Answer for part E: \triangle SXR \cong \triangle TXR
Answer for part F: CPCTC

-------------------------------------------------------------

Explanations:

Part A:

We are given that \overline{RX} \perp \overline{ST} which means, in english, "line segment RX is perpendicular to line segment ST"

By the very definition of perpendicular, this means that the two line segments form a right angle. This is visually shown as the red square angle marker for angle RXT. Angle RXS is also a right angle as well.

---------------------
Part B:

The Right Angle Congruence Theorem (aka Right Angle Theorem) is the idea that if we have two right angles, then we know that they are both 90 degrees so they must be congruent to one another. 

---------------------
Part C:

Any line segment is congruent to itself. This is because any line segment will have the same length as itself. It seems silly to even mention something so trivial but it helps establish what we need for the proof. 

---------------------
Part D:

We are given "X is the midpoint of segment ST" so by definition, X is in the very exact middle of ST. Midpoints cut segments exactly in half. SX is one half while TX is the other half. The two halves are congruent which is why SX = TX

---------------------
Part E:

Writing \triangle SXR \cong \triangle TXR means "triangle SXR is congruent to triangle TXR". These two triangles are the smaller triangles that form when you draw in segment RX

Side Note: SAS stands for "side angle side". The angle must be between the two sides. The pairing RX and RX forms one of the 'S' letters (see part C), while the pairing SX and TX forms the other 'S' (see part D). The angles between the sides are RXS and RXT (see part B). 

---------------------
Part F:

CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent"

It means that if we have two congruent triangles, then the corresponding parts are congruent. Back in part E, we proved the triangles congruent. For this part, we look at the pieces RS and RT (which correspond to one another; they are the hypotenuse of each triangle). They are proven congruent by CPCTC

If CPCTC is an odd concept to think about, then try thinking about something like this: you have two houses which are completely identical in every way. We can say that those two houses are congruent. If the houses are identical, then surely every piece that makes up the house is identical to its corresponding piece to the other house. For example, the front door to each house is both the same size, shape, color, made of the same material, designed in the same pattern, etc. So the two doors are congruent as well.
8 0
3 years ago
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