W=12.5c+39.2
Her collection already has a weight of 39.2 g so you must add that to every new car bought each with a weight of 12.5 g.
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have


case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1


case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2


Answer:
It is an identity, the proof is in the explanation
Step-by-step explanation:
csc(A)-cot(A)=tan(A/2)
I'm going to start with right hand side
tan(A/2)=(1-cos(a))/(sin(a)) half angle identity
tan(A/2)=1/sin(a)-cos(a)/sin(a) separate fraction
tan(A/2)=csc(a)-cot(a) reciprocal and quotient identities
The graph of the equation given by y=-cos³θ will be as follows: