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jok3333 [9.3K]
2 years ago
15

Is this a right triangle yes or no ?​

Mathematics
1 answer:
slega [8]2 years ago
3 0

Answer:

I don't think so, regular triangle sizes are 3, 4,5. If I am wrong please tell me.

Step-by-step explanation:

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Choose all the expressions that are equal to 5/9×8. A. 9÷5×8 B. 8/9×5 C. 5÷8×9 D. 5×1/9×8 E. 5×8
Charra [1.4K]
<h2>Problem:</h2>

Choose all the expressions that are equal to 5/9×8.

A. 9÷5×8

B. 8/9×5

C. 5÷8×9

D. 5×1/9×8

E. 5×8

<h2>Solution:</h2>

\purple{ \frac{5}{9}  \times 8 =  \frac{40}{9}  = 4 \:  \frac{4}{9} }

\red{9 \div 5 \times 8 =  \frac{9}{5}  \times 8 =  \frac{72}{5}  = 14 \:  \frac{2}{5} }

\red{ \frac{8}{9}  \times 5 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \div 8 \times 9 =  \frac{5}{8}  \times 9 =  \frac{45}{8}  = 5 \:  \frac{5}{8} }

\red{5 \times  \frac{1}{9}  \times 8 =  \frac{5}{9}  \times 8 =  \frac{40}{9}  =  \boxed{4 \:  \frac{4}{9} }}

\red{5 \times 8 = 40}

<h2>Answer:</h2>

<u>B</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>D</u>

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
5 0
3 years ago
Let ​ f(x)=x2−8x+19 ​ . What is the minimum value of the function?​ Enter your answer in the box. ​
ella [17]
The minimum value is 3.
6 0
3 years ago
Read 2 more answers
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac
valentinak56 [21]

Answer:

tan(θ) = 0, 0.577, -0.577

Step-by-step explanation:

3tan³(θ) - tan(θ) = 0

tan(θ)(3tan²(θ) - 1) = 0

tan(θ) = 0

tan²(θ) = ⅓ tan(θ) = +/- sqrt(⅓)

tan(θ) = 0, sqrt(⅓), -sqrt(⅓)

tan(θ) = 0, 0.577, -0.577

To find θ values, domain is required

6 0
3 years ago
22 8(11 + 2r) = 126r + 3
natulia [17]

8(11 + 2r) = 126r + 3​

first open the parenthesis

88 + 16r = 126r + 3

88 - 3 = 126r - 16 r

85 = 110r

divide both-side of the equation by 110

85/110 = r

r= 17/22

7 0
1 year ago
A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height​ h, in​ feet, after t seconds is
olchik [2.2K]
Check the picture below.

thus is at 0 = -16t² + 96t +640,

\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)&#10;\\\\\\&#10;0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=&#10;\begin{cases}&#10;\boxed{10}\\&#10;-4&#10;\end{cases}

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0
3 years ago
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