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Dmitrij [34]
3 years ago
15

In a certain physics experiment, carts run along a frictionless, level track. Cart A is 1 kg and Cart B is 2 kg. Initially cart

A is moving to the right at 3.0 m/s and cart B is moving to the left at 7.0 m/s. After they collide, they stick together. What is the magnitude of the velocity of the two carts?
Physics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:v=-\frac{11}{3} m/s \left

Explanation:

Given

Mass of car A\left ( m_a\right )=1 kg

Mass of car B\left ( m_b\right )=2 kg

velocity of cart A=3 m/s

velocity of cart B=-7 m/s

Conserving momentum

m_au_a+m_bu_b=\left ( m_a+m_b\right )v

v=\frac{m_au_a+m_bu_b}{\left ( m_a+m_b\right )}

v=-\frac{11}{3} m/s \left ( i.e. in\ left\right )

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An outside force, Fo, brings two small metal spheres, A and B, at rest from a long distance away to a point where they are 1 met
Ksenya-84 [330]

Answer:

1)

The total work done by outside force is W_{o}=0.294J

2)

The total work done by the electric field is -W_{o} =-0.294J

3)

The potential energy of the two sphere system is  PE = W_{o} = 0.294J

4)

The magnitude of the acceleration of sphere A is a_{A} = 66.868m/s^2

5)

The magnitude of the acceleration of sphere B is a_{B} = 26.747 \ m/s^2

6)

The magnitude of velocity sphere A after a very long time is  v_{A} = 10.251 \ m/s\

7) The magnitude of velocity sphere B after a very long time is  v_{B} = 4.1 m/s

 

Explanation:

The explanation is shown on the first and second uploaded image

4 0
3 years ago
A convex lens of focal length 25 cm is in contact with a concave lens of focal length 50 cm. The equivalent focal length of this
Gwar [14]

The equivalent focal length of this combination-lenses should be +50 cm.

Given:

Focal length of convex lens, f₁ = +25 cm

Focal length of concave lens, f₂ = -50 cm

Calculation:

We know that the power of a lens is given as:

P = 1 / f

where, f is the focal length of lens

Now, the power of convex lens can be calculated as:

P₁ = 1/f₁

  = 1/(25×10⁻² m)

  = 100/25

  = +4 D

Similarly, the power of concave lens can be calculated as:

P₂ = 1/f₂

    = (1/-50×10⁻² m)

    = -100/50

    = -2 D

Thus, the power of the combined lenses can be calculated as:

P₍₁₊₂₎ = P₁ + P₂

       = +4 D - 2 D

       = +2 D

Now, the combined focal length of the lens can be calculated as:

f₍₁₊₂₎ = 1 / P₍₁₊₂₎

      = 100 / 2 D

      = +50 cm

Therefore, the equivalent focal length of this combination-lenses will be +50 cm.

Learn more about mirrors and lenses here:

<u>brainly.com/question/3209252</u>

#SPJ4

6 0
2 years ago
A 0.25 kg mass is placed on a vertically oriented spring that is stretched 0.56 meters from its equilibrium position. If the spr
Vitek1552 [10]

Answer:

The speed of the ball when it reaches equilibrium position is 3.31 m/s

Explanation:

Given;

mass of the object, m = 0.25 kg

initial displacement of the object, h₁ = 0.56 m

spring constant, k = 105 N/m

displacement at equilibrium position, h₂ = 0

initial velocity of the object, v₁ = 0

velocity of the object at equilibrium position = v₂

The change in gravitational potential energy at the equilibrium position is given as;

ΔP.E = mg(h₂ - h₁)

The change in kinetic energy of the object at the equilibrium position is given as;

ΔK.E = ¹/₂m(v₂² - v₁²)  

Apply the principle of conservation of mechanical energy;

ΔK.E  +  ΔP.E = 0

¹/₂m(v₂² - v₁²)  +  mg(h₂ - h₁) = 0

¹/₂m(v₂² - 0)  +  mg(0 - h₁) = 0

¹/₂mv₂²  -  mgh₁  =  0

¹/₂mv₂²  = mgh

¹/₂v₂² = gh

v₂² = 2gh

v₂ = √2gh

v₂ = √(2 x 9.8 x 0.56)

v₂ = 3.31 m/s

Therefore, the speed of the ball when it reaches equilibrium position is 3.31 m/s

8 0
3 years ago
50 points;
inna [77]

A : lighter than lead shot, reducing its velocity and distance

4 0
4 years ago
Electrically charged sunspot gases which escape the sun's chromosphere and enter the earth's atmosphere near the magnetic north
Kisachek [45]

Answer:

Northern Lights ( Aurora Borealis)

Explanation:

When the electricaly charged sunspot gases (they are named a solar wind) escape the sun's chromosphere and penetrates from the earth magnetic sheild which is called earth's magnetosphere then upon there interaction with atoms and molecules of our atmosphere there are little bursts of photons in the form of light which made up these northern lights.

6 0
3 years ago
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