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pantera1 [17]
2 years ago
5

Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the co

mpressor if the inlet volumetric flow rate is 0.15 m3/s. Use constant specific heats evaluated at 300 K.
Physics
1 answer:
ladessa [460]2 years ago
5 0

Answer:

\dot W_{in} = 49.386\,kW

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

\dot W_{in} + \dot m \cdot c_{p}\cdot (T_{1}-T_{2}) = 0

The power consumed by the compressor can be calculated by the following expression:

\dot W_{in} = \dot m \cdot c_{v}\cdot (T_{2}-T_{1})

Let consider that air behaves ideally. The density of air at inlet is:

P\cdot V = n\cdot R_{u}\cdot T

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

\rho = \frac{P\cdot M}{R_{u}\cdot T}

\rho = \frac{(104\,kPa)\cdot (28.02\,\frac{kg}{kmol})}{(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (292\,K)}

\rho = 1.2\,\frac{kg}{m^{3}}

The mass flow through compressor is:

\dot m = \rho \cdot \dot V

\dot m = (1.2\,\frac{kg}{m^{3}})\cdot (0.15\,\frac{m^{3}}{s} )

\dot m = 0.18\,\frac{kg}{s}

The work input is:

\dot W_{in} = (0.18\,\frac{kg}{s} )\cdot (1.005\,\frac{kJ}{kg\cdot K})\cdot (565\,K-292\,K)

\dot W_{in} = 49.386\,kW

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Rama09 [41]

Answer:

(a) 0.613 m

(b) 0.385 m

(c) vₓ = 1.10 m/s, vᵧ = 3.50 m/s

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Explanation:

(a)  Take down to be positive.

Given in the y direction:

v₀ = 0 m/s

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Δy = (0 m/s) (0.350 s) + ½ (10 m/s²) (0.350 s)²

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(b) Given in the x direction:

v₀ = 1.10 m/s

a = 0 m/s²

t = 0.350 s

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Δx = v₀ t + ½ at²

Δx = (1.10 m/s) (0.350 s) + ½ (0 m/s²) (0.350 s)²

Δx = 0.385 m

(c) Find: vₓ and vᵧ

vₓ = aₓt + v₀ₓ

vₓ = (0 m/s²) (0.350 s) + 1.10 m/s

vₓ = 1.10 m/s

vᵧ = aᵧt + v₀ᵧ

vᵧ = (10 m/s²) (0.350 s) + 0 m/s

vᵧ = 3.50 m/s

The magnitude is:

v² = vₓ² + vᵧ²

v = 3.68 m/s²

The direction is:

θ = atan(vᵧ / vₓ)

θ = 72.6° below the horizontal

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hjlf

Answer:

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