All categories

3 years ago

Find the solution of the system of equations shown on the graph

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

The solution is the point of intersection, (5,-10)

You might be interested in

A thermometer has a percent error of 3%. The actual temperature is 75°F.

lesantik [10]

1.) 72.75

2.)77.25

im also doing this so the guy under me can get brainliest :P

6 0

3 years ago

Read 2 more answers

Factor completely 4(x+1)^2/3 + 12(x+1)^-1/3

wolverine [178]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\
-------------------------------\\\\
%4(x+1)^2/3 + 12(x+1)^-1/3
4(x+1)^{\frac{2}{3}}+12(x+1)^{-\frac{1}{3}}\implies 4(x+1)^{\frac{2}{3}}+12\cfrac{1}{(x+1)^{\frac{1}{3}}}
\\\\\\$

$\bf 4(x+1)^{\frac{2}{3}}+\cfrac{12}{(x+1)^{\frac{1}{3}}}\impliedby \textit{so, our LCD is }(x+1)^{\frac{1}{3}}
\\\\\\
\cfrac{4(x+1)^{\frac{2}{3}}\cdot (x+1)^{\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)^{\frac{2}{3}+\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4(x+1)^{\frac{3}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4x+4+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4x+16}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+4)}{\sqrt[3]{x+1}}$

3 0

3 years ago

Read 2 more answers

-3(6) + 2(3) - 18 = 6 Is this incorrect or correct and why ?

KiRa [710]

It is incorrect because when you times a negative by a positive. It is a negative number.

6 0

3 years ago

(2x + y)2 – (3x – 2y)2 + (x – 4y)(x + 4y 11

Vinvika [58]

Answer:

Step-by-step explanation:

(a+ b)² = a² + b² + 2ab

(2x + y)² = (2x)² + y² + 2*2x *y

= 4x² + y² + 4xy

(a- b)² = a² + b² - 2ab

(3x - 2y)² = (3x)² + (2y)² - 2*3x *2y

= 9x² + 4y² - 12xy

(a - b)(a +b) = a² - b²

(x - 4y(x + 4y) = x² - (4y)²

= x² - 16y²

(2x + y)² - (3x - 2y)² + (x - 4y)(x +4y)

= 4x² + y² + 4xy - (9x² + 4y² - 12xy) + x² - 16y²

= 4x² + y² + 4xy - 9x² - 4y² + 12xy + x² - 16y²

= 4x² - 9x² + x² + y² - 4y² - 16y²+ 4xy + 12xy

= -4x² - 19y² + 16xy

8 0

3 years ago

G=3t^2−5t+6 P=−8t^2+7t−9 G+P=

kotykmax [81]

Answer:

-5t^2 +2t -3

Step-by-step explanation:

Collect terms in the sum:

G+P = (3t^2 -5t +6) +(-8t^2 +7t -9) = (3-8)t^2 +(-5+7)t +(6-9)

= -5t^2 +2t -3

3 0

3 years ago