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agasfer [191]
3 years ago
8

A prime polynomial cannot be written as a product of lower-degree polynomials. Which polynomial is prime? a)8x2 – 10x – 3 b)8x2

+ 2x – 3 c)8x2 – 6x – 3 d)8x2 + 23x – 3
Mathematics
2 answers:
Basile [38]3 years ago
10 0
As already described above, the prime polynomial is that which can no longer be factored to yield a much simpler terms. From the given choices, that which cannot be factored is letter C. 
otez555 [7]3 years ago
10 0

Answer:

The correct option is c.

Step-by-step explanation:

Option a,

8x^2-10x-3

8x^2-12x+2x-3

4x(2x-3)+(2x-3)

(2x-3)(4x+1)

A prime polynomial cannot be written as a product of lower-degree polynomials. Therefore option a is not prime.

Similarly find the factors of other expressions.

8x^2+2x-3

8x^2-6x+4x-3

2x(4x-3)+(4x-3)

(2x+1)(4x-3)

Therefore option b is not prime.

8x^2-6x-3

This polynomial factored further and cannot be written as a product of lower-degree polynomials.  Therefore it is prime and option c is correct.

8x^2+23x-3

8x^2+24x-x-3

8x(x+3)-(x+3)

(8x-1)(x+3)

Therefore option d is not prime.

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A pen costs twice as much as a pencil. The total cost of 1 pen and 1 pencil is $2.10. If p represents the cost of 1 pencil, whic
oksano4ka [1.4K]

Answer:

A:2p+p=10

Step-by-step explanation:

3 0
3 years ago
The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se
Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

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He initial value is 32,000 and the value after 13 yrs is 8133.97
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Solve each equation.<br> Show all steps<br> 4) -8(-6-5k)=-232
Lubov Fominskaja [6]

the answer is k=4.6. hope this helps

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