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agasfer [191]
3 years ago
8

A prime polynomial cannot be written as a product of lower-degree polynomials. Which polynomial is prime? a)8x2 – 10x – 3 b)8x2

+ 2x – 3 c)8x2 – 6x – 3 d)8x2 + 23x – 3
Mathematics
2 answers:
Basile [38]3 years ago
10 0
As already described above, the prime polynomial is that which can no longer be factored to yield a much simpler terms. From the given choices, that which cannot be factored is letter C. 
otez555 [7]3 years ago
10 0

Answer:

The correct option is c.

Step-by-step explanation:

Option a,

8x^2-10x-3

8x^2-12x+2x-3

4x(2x-3)+(2x-3)

(2x-3)(4x+1)

A prime polynomial cannot be written as a product of lower-degree polynomials. Therefore option a is not prime.

Similarly find the factors of other expressions.

8x^2+2x-3

8x^2-6x+4x-3

2x(4x-3)+(4x-3)

(2x+1)(4x-3)

Therefore option b is not prime.

8x^2-6x-3

This polynomial factored further and cannot be written as a product of lower-degree polynomials.  Therefore it is prime and option c is correct.

8x^2+23x-3

8x^2+24x-x-3

8x(x+3)-(x+3)

(8x-1)(x+3)

Therefore option d is not prime.

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Answer:

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If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

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Wow! Thank you for an interesting question with a not-so-obvious answer.

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<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

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XYZ has coordinates X(2, 3), Y(1,4), and Z(8,9). A translation maps X to X'(4,7). What are the coordinates for Y' and Z' for thi
Rashid [163]

Answer:

The coordinates are Y'(x,y) = (3, 8) and Z'(x,y) = (10, 13).

Step-by-step explanation:

First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:

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Where T(x,y) is the vector translation.

If we know that X(x,y) = (2,3) and X'(x,y) = (4,7), then the vector translation is:

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T(x,y) = (4,7) - (2,3)

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Then, we determine the coordinates for Y' and Z':

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Y'(x,y) = (3, 8)

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