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3 years ago

?? ihow to solve this problem

Mathematics

1 answer:

postnew [5]3 years ago

4 0

In the given formula :

r = rate = 4.5% = 0.045

t = time = 7 years

P = principal = #3,700

e is an arbitrary number used in mathematics, which is approximately 2.7183

Replace the letters with the given information:

A = 3700e^0.045(7)

A = $5,069.96

The answer is C

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The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the

son4ous [18]

L = 59+2w
diagonal = 2+l

diagonal^2 = l^2 +w^2

(2+l)^2 = l^2 +w^2

4 +4l +l^2 = l^2 +w^2

4+4l =w^2

l = 59+2w

4+4(59+2w)=w^2

4+236+8w=w^2

w^2 -8w -240 =0

D = 64 +960 = 1024

w_1,2 = (8+/-sqrt1024)/2 = -12 and 20

l=59+2*20=59+40=99

l=99
w=20

hope helped

6 0

2 years ago

Which correctly describes the effects on

goblinko [34]

The answer is... A

Because

F is steeper than the graph of f(x)

5 0

2 years ago

I NEEED HEEELLLPP

cricket20 [7]

Answer:

c) T(−1, 3) ° Rotation,180°

Step-by-step explanation:

Explanation:-

First we will apply transformation is

Rotation of 180° then we will apply transformation is changes

(x,y) to (-x ,-y)

a)

Given vertex T( 2 ,2 )

T( 2 ,2 )→ T( -2 ,-2)

Next we will apply rule

Horizontal translation left '1' units and Vertical translation up 'd' units

T( -2 ,-2) → T¹ ( -2 -1 ,-2 +3)

The new vertex is T¹ ( -3 ,1)

b)

Given vertex U( 4 ,2 )

U( 4 ,2 )→ U( -4 ,-2)

Next we will apply rule

Horizontal translation left '1' units and Vertical translation up 'd' units

U -4 ,-2) → U¹ ( -4 -1 ,-2 +3)

The new vertex is U¹ ( -5 ,1)

c)

Given vertex R( 3 ,5 )

R( 3 ,5 )→ R( -3,-5)

Next we will apply rule

Horizontal translation left '1' units and Vertical translation up 'd' units

R( -3 ,-5) → R¹ ( -3 -1 ,-5 +3)

The new vertex is R¹ ( -4 ,-2)

d)

Given vertex S( 1 ,3 )

S( 1 ,3 )→ S( -1 ,-3)

Next we will apply rule

Horizontal translation left '1' units and Vertical translation up 'd' units

S( -1,-3) → S¹ ( -1 -1 ,-3 +3)

The new vertex is S¹ ( -2,0)

6 0

3 years ago

An equation of the line passing through points B and D is

noname [10]

Answer:

maths

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7 0

3 years ago

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An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest

nadya68 [22]

The equation for exponential decay is $y=a*b^x$ , where a is the initial amount, b = 1 + r (the growth rate as a decimal number) and x is the number of time periods (in this case, minutes). Substituting the information we have:
$y=430(1+-0.274)^1^9
\\=430(1-0.274)^1^9
\\=430(0.726)^1^9=0.98$ . To the nearest tenth of a gram, this would be 1.0 grams.

7 0

3 years ago