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Zarrin [17]
3 years ago
15

a store sold a total of 15,000 boxes of buttons last month and 12,000 boxes this month. if the store sold 270,000 buttons, how m

any buttons were in each box?
Mathematics
2 answers:
Reptile [31]3 years ago
5 0
15000+12000=27000
270000/27000=10
10 buttons per box
eduard3 years ago
5 0

Answer: There are 10 buttons in each box.

Step-by-step explanation:

Since we have given that

Number of boxes a store sold in last month = 15,000

Number of boxes a store sold in this month = 12,000

Total number of boxes would be

15,000+12,000=27,000

Number of buttons a store sold = 270,000

So, Number of buttons were in each box would be

\dfrac{270,000}{27000}\\\\=10

Hence, there are 10 buttons in each box.

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Solve for B: AB + 3C = D
Brilliant_brown [7]

If we want to get B by itself, we need to "undo" every operation being done to it. Those operations are (in order):

  • Multiplication by A
  • Addition with 3C

To undo these then, we'll need to:

  • Subtract 3C
  • Divide by A

And, since this is an equation, we'll need to do both of those to the right side as well to keep everything equal. Here we go:

AB + 3C - 3C = D - 3C (subtracting 3C)

AB/A = (D - 3C)/A (dividing by A)

B = (D - 3C)/A

And we're done! If you'd like to see it formatted a little nicer, here's this:

B=\dfrac{D-3C}{A}

3 0
3 years ago
Question 3: In les Miserables Monsier, Thenardier, and Madame Thenardier are married and during act two, Cosette and Marius beco
Natasha2012 [34]
Answer: 14,515,200

Note: this is a single number (not an ordered triple or a collection of three different numbers) roughly equal to about 14.5 million if you round to the nearest hundred thousand.

----------------------------------------------

Explanation:

There are 13 people. Let's call them person A, person B, person C, ... all the way up to person M. The first four people are given who we'll call A through D. The rest (E through M) aren't really important since they aren't named. 

A = Monsier Thenardier
B = Madame Thenardier
C = Cosette
D = Marius
Peron's E through M = remaining 9 people

------------------

A and B must stick together. Because of this, we can consider "AB" as one "person".
So we go from 13 people to 13-2+1 = 12 "people". 

Likewise, C and D must stick together. We can consider "CD" as one "person". So we go from 12 "people" to 12-2+1 = 11 "people"

------------------

The question is now: how many ways can we arrange these 11 "people" around a circular table? The answer is (n-1)! ways where n = 11 in this case

So, (n-1)! = (11-1)! = 10! = 10*9*8*7*6*5*4*3*2*1 = 3,628,800

We're almost at the answer. We need to do two adjustments. 

First off, for any single permutation, there are two ways to arrange "AB". The first is "AB" itself and the second is the reverse of that "BA". So we will multiply 3,628,800 by 2 to get 2*3,628,800 = 7,257,600

Using similar logic for "CD", we double 7,257,600 to get 2*7,257,600 = 14,515,200

The final answer is 14,515,200


7 0
3 years ago
NEED HELP DUE AT 11:25
Alja [10]

Answer:

w=p/2-l

Step-by-step explanation:

you have to simplify the equation p=2(l+w).

1) Isolate the variables l and q

p/2=l+w

2) Subtract the length from the width.

p/2-l=w

3) The answer is b, or w=p/2-l

8 0
2 years ago
Solve the proportion 84/12 = 28/X
Leviafan [203]
7 would be your answer
5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
rosijanka [135]

Answer:

Area of the other polygon = 4 in.²

Step-by-step explanation:

Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon

Let "x" represent the area of the smaller polygon

Thus, we have:

100/x = 20²/4²

100/x = 400/16

100/x = 25

Cross multiply

25x = 100

Divide both sides by 25

25x/25 = 100/25

x = 4

Area of the other polygon = 4 in.²

8 0
3 years ago
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