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kotegsom [21]
3 years ago
15

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a​ single-strand electric

fence. With 19001900 m of wire at your​ disposal, what is the largest area you can​ enclose, and what are its​ dimensions?
Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0
I'm fairly certain that using that wire you can have the same area no matter what dimensions there are, but if you do the square root, or \sqrt{} of 19,001,900 then you get 4359.11688. So your dimensions are 4359.11688 x 4359.11688. To get area, do length x width to get <span>1.9*1 0^{7}.

Hope this helped! If it did, please give me a good rating and mark me brainiest.<span /></span>
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Which of the following equations would not have a solution that is the same as the solution to the system. shown below?
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Step-by-step explanation:

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Jocelyn's foot is 17 centimeters long. If she puts the heel of one foot next to the toes of her other foot, how long will both o
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Which trinomials are perfect square trinomials?
lora16 [44]
Perfect square is
a²+2ab+b²

so just take the square root of the end ones and add then double to get middle term


A.
m+10=10m, doubled is 20m
nope

B.
m+5=5m, doubled is 10m, yep

C.
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D.
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B and D
3 0
3 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
Carla paid $129 plus 6% sales tax for a guitar. What
Nesterboy [21]

Answer:

136.74

Step-by-step explanation:

6 percent of $129 is $7.74

129 plus 7.74 = 136.74

4 0
2 years ago
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