The general approach to this is to write the (x, y) coordinates of the trajectory's peak in terms of the sine and cosine of the launch angle α. Then use a trig identity (sin(2α)² + cos(2α)² = 1) to eliminate the dependence on α.
You should get
t = v₀sin(α)/g
x = v₀²sin(2α)/(2g)
y = v₀²(1-cos(2α))/(4g)
Solve each of the latter two equations for the trig function, then substitute those expressions into the trig identity above. Divide by the coefficient of x² and rearrange to get the expression shown.
Answer:
160
Step-by-step explanation:
v^2 = 64d
d = 400
v^2 = 64*400
v = sqrt of (64*400) = 160
ANSWER: B 7/22
I hope this helped
Hey!
To solve this problem we must begin by writing out an equation.
Here's the equation I've created.
<em>520 ÷ </em><span><em>453.592 = ?</em>
Now we solve our created equation to get the answer.
<em>520 </em></span><em>÷ 453.592 = 1.1464046985</em>
That could be our final answer but sometimes you might want to round.
<em>So, the tires weight in pounds is</em> 1.1464046985 <em>or</em> 1.15.
Hope this helps!
- Lindsey Frazier ♥
A. 4times y+2 b. 5-x times 3 times y c. -2 times y-3 d. -7 times 4+x e. 16 times x -8 divided by 4 f. 1 divided by 3 times 2 times x +3
sorry I tried to make it out the best that I could I don't have all the symbols so I just wrote out the divide and multiply parts