3 years ago

The measures of the angeles of Δ RST are given by the expressions in the table

1 answer:

3 0

For the second angle, I'll take it as x + 4, I think you had a typo
the angle sum of triangle is 180, so just add all of them.
180 = 31 + x + 4 + 3x +9
180 = 4x + 44
4x = 136
x = 34
as x = 34,
s = 34 + 4
= 38
T = 3 x 34 + 9
= 102 + 9
= 111

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Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of $x^3+6x^2-9x-54$

Solving

$x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)$

Taking x^2 common from first 2 terms and -9 from last two terms we get

$=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\$

Taking (x+6) common

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Putting it equal to zero,

$(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\, x=3$

So, Option B 3,-3,-6 is correct.

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