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Evgesh-ka [11]
3 years ago
15

How do I solve these problems?

Mathematics
1 answer:
lesya [120]3 years ago
5 0

Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D

\log x=5.6-\log7.5\ \ \ \ |+\log7.5\\\\\log x+\log7.5=5.6\ \ \ \ |use\ \log x+\log y=\log (xy)\\\\\log(7.5x)=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\7.5x=10^{5.6}\ \ \ \ |:7.5\\\\\boxed{x=\dfrac{10^{5.6}}{7.5}}\in D

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14 subtracted from 5 times a number is 6
kkurt [141]
It's 5x - 14 = 6.

let x be the number.

Since 14 is subtracted from 5 times a number. It is not automatically 14 - 5. you have to consider that 14 is actually deducted from the product of 5 and a number.

5x - 14 = 6
5x = 6 + 14
5x = 20
5x/5 = 20/5
x = 4

To check:
5x - 14 = 6
5(4) - 14 = 6
20 - 14 = 6
6 = 6

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PS I just tried this problem on my calculator, so I don't know if I did it right, but it makes sense to me. I also searched it up and it also says it's 780, so I'm guessing it's correct. The way I showed you is easier though.

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