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Evgesh-ka [11]
3 years ago
15

How do I solve these problems?

Mathematics
1 answer:
lesya [120]3 years ago
5 0

Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D

\log x=5.6-\log7.5\ \ \ \ |+\log7.5\\\\\log x+\log7.5=5.6\ \ \ \ |use\ \log x+\log y=\log (xy)\\\\\log(7.5x)=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\7.5x=10^{5.6}\ \ \ \ |:7.5\\\\\boxed{x=\dfrac{10^{5.6}}{7.5}}\in D

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Leonard and Liam each own a collection of vintage cars. Leonard has 7 cars more than Liam has. Three times the number of cars Le
dimulka [17.4K]

Answer: The answer is (22, 15).

Step-by-step explanation:  Given that 'x' represents the number of cars Leonard has and 'y' represents the number of cars Liam has.

Then, according to the given information, we have

x-y=7,\\\\3x+2y=96.

Multiplying the first equation by 2 and adding to the second equation, we have

2x+3x=14+96\\\\\Rightarrow 5x=110\\\\\Rightarrow x=22.

So,

y=x-7=22-7=15.

Therefore, Leonard has 22 cars and Liam has 15 cars.

Thus, (22, 15) is the solution to the given system.

5 0
3 years ago
Read 2 more answers
Which best describes the probability of rolling a 7 on a number cube that is numbered from 1 through 6?
Snowcat [4.5K]
The answer is A, it can't land on a number that doesn't exist.
7 0
3 years ago
Use the diagram below & your knowledge of inscribed angles of a quadrilateral to label the measures of EACH inscribed angle
Marrrta [24]

Answer:

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Step-by-step explanation:

Sorry I can't help but I hope you got it

8 0
2 years ago
6.
larisa86 [58]

A. Every month Population will increase by a factor of 0.84%.

B.  Every 3 months Population will increase by a factor of 2.5%.

C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.

<u>Step-by-step explanation:</u>

Here, we have  number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as  x + \frac{x}{100}\times10 which is equivalent to \frac{11x}{10}.

<u>A.</u>

For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like \frac{10}{12}  = 0.84 . ∴ Every month Population will increase by a factor of 0.84%.

<u>B.</u>

In every 3 months: We have , 12 months in a year , in order to check for every 3 months  \frac{12}{3} = 4 and Now, Population increase in every 3 months is \frac{10}{4}  = 2.5.  ∴ Every 3 months Population will increase by a factor of 2.5%.

<u>C.</u>

In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.

So , increase in population in every 20 months is 10% + 6.72% = 16.72%.

5 0
3 years ago
Millions of years ago, the Indian plate began pushing gradually towards the Eurasian plate. The land above started rising in var
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Folded mountain with waves, twists, and turns. I believe because the article stated it was gradual and various patterns were formed.
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