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Evgesh-ka [11]
3 years ago
15

How do I solve these problems?

Mathematics
1 answer:
lesya [120]3 years ago
5 0

Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D

\log x=5.6-\log7.5\ \ \ \ |+\log7.5\\\\\log x+\log7.5=5.6\ \ \ \ |use\ \log x+\log y=\log (xy)\\\\\log(7.5x)=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\7.5x=10^{5.6}\ \ \ \ |:7.5\\\\\boxed{x=\dfrac{10^{5.6}}{7.5}}\in D

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Simplify: (sin θ − cos θ)^2 − (sin θ + cos θ)^2 A) −4sin(θ)cos(θ) B) 2 C) sin^2 θ D) cos^2 θ
N76 [4]

Answer:

-4sinθcosθ

Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)

= 1 - 2sinθcosθ - (1 + 2sinθcosθ)

= 1- 2sinθcosθ -1 - 2sinθcosθ

= - 2sinθcosθ - 2sinθcosθ

= -4sinθcosθ

3 0
3 years ago
A parabola has a vertex at (-2,6) and roots at 7 and m. Find the value of m
Archy [21]

Answer:

So m= - 11

Step-by-step explanation:

* THe vertex is (-2,6), then the equation is y = a(x+2)^2 +6, a is to find out.

* A root is 7 means x=7 and y=0, then :

0 = a(7+2)^2 +6

0=81a+6 or a= -6/81  = -2/27.

* We have the equation: y= -2/27 (x+2)^2 +6=-2/27 [ (x+2)^2-81]

y= -2/27 (x-7)( x+11).

So m= - 11

Hope that you understand.

8 0
4 years ago
Chin canned a number of quart jars anf a number of pints jars of tomatoes from hid garden. A pint is 16 onces and a quart is 32
ryzh [129]

Answer:

The equation which models the scenario is:   16 p + 32 q  = 1280

Step-by-step explanation:

The total number of pints packed  = p

The total number of quarts  packed  = q

The weight of 1 pint jar of tomatoes  = 16 oz

So, the total weight of p pints  = p x ( Weight of 1 pint) = p x ( 16 oz) = 16 p

The weight of 1 quart jar of tomatoes  = 32 oz

So, the total weight of q quarts  = q x ( Weight of 1 quart) = q x ( 32 oz)

= 32 q

Now, the TOTAL WEIGHT of p pints and q quarts

= Total weight of { p pints +  q quarts}  = 16 p + 32 q

Also, chin canned a total of 1280 ounces.

⇒ TOTAL WEIGHT of p pints and q quarts = 1280 ounces

or,   16 p + 32 q  = 1280 ounces

Hence, equation which models the scenario is:   16 p + 32 q  = 1280

8 0
3 years ago
A square billboard has an area of 625 ft squared. What is the length of the side of the billboard?
goldenfox [79]

Answer:

figured it out is 25

Step-by-step explanation:

hope this helps:)

3 0
3 years ago
If angles are congruent, solve by setting expressions equal to each other.<br><br> True<br> False
Taya2010 [7]
Answer: True, angles that are congruent are equaled to each other
3 0
3 years ago
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