39=9x+7-3x+20
Subtract 27 from each side
12=6x
2=x
Now plug in 2 for x to find AB and BC
9x+7= AB
9(2)+7=AB
18+7= AB
25= AB
-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC
We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
Answer:
Option b is the correct answer
Step-by-step explanation:
The graph in the picture is the graph of a quadratic equation and it takes the shape of a parabola.
The points on the x axis through which the parabola cuts across is used to determine the solution of the quadratic equation.
Looking at the parabola formed from the plotted points, it cuts the x axis at
x = -1 and x= -2
These are the factors of the equation. To get the equation, we multiply the factors.
x= -1, x +1 = 0
x =-2 , x + 2= 0
The equation is (x+1)(x+2)
Expanding the brackets,
x×x + x×2 +1×x + 1×2
= x^2 + 2x + x +2
= x^2 + 3x +2 = 0
Option b is the correct answer
Answer:
As we have seen before, you can write the equation of any line in the form of y = mx + b . This is the so-called slope intercept form, because it gives you two important pieces of information: the slope m and the y-intercept b of the line. You can use these values for linear interpolation later.
Step-by-step explanation:
