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Ludmilka [50]
3 years ago
8

A gardener determines the cost of planting daffodil bulbs to be $2.40 per square foot. How much will it cost to plant daffodil b

ulbs in a rectanglular garden that is 12 feet longand 5 feet wide?
A)$40.80

B)$60

C)$144

D)$81.60
Mathematics
2 answers:
mafiozo [28]3 years ago
7 0
C
(12*5)*$2.40
first calculate to total square feet of the garden, then times that my the price of light bulbs
deff fn [24]3 years ago
5 0
The answer to your question is C) $144
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Simplify 4/9 + 1/3<br> A 5/12<br> B 7/9<br> C 1 1/9<br> D 15/9
ELEN [110]

Answer:

B) 7/9

Step-by-step explanation:

<h3>Fraction addition:</h3>
  • If the denominators are not same, find the LCM of the denominators.

          LCM of 3 and 9 is 9.

  • Now, find equivalent fractions with denominator as 9.

          \sf \dfrac{1}{3}=\dfrac{1*3}{3*3}\\\\

              \sf =\dfrac{3}{9}

  • Now add.

      \sf \dfrac{4}{9}+\dfrac{1}{3}=\dfrac{4}{9}+\dfrac{3}{9}\\\\

                 \sf =\dfrac{7}{9}

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In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

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Step-by-step explanation:

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