Answer:
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
reduce fraction:
By using calculator we acquire:
hence, the remaining sample after 420 days is 0.625 kg
Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Answer:
Step-by-step explanation:
180-96
180-96 = 84
96 + 84 = 180
To solve this equation with algebra
4/7 = 1/x
(4/7)x = (1/x)x
4x/7 = 1
(4x/7)7 = 1(7)
4x = 7
4x/4 = 7/4
x = 1.75
1.75 yards of fabric are needed to make 1 dress.
Hope this helps! <3
Answer:
$2.50+$1.25 times M
Step-by-step explanation:
$10.75-$8.25=$2.50
$3.50-$2.25=$1.25
$2.50+$1.25=$3.75
As only one-time fee, we cancel out it, then only add on the per-month fee, which is $1.25 every month.
