Answer:
10.9361
Step-by-step explanation:
The lower control limit for xbar chart is
xdoublebar-A2(Rbar)
We are given that A2=0.308.
xdoublebar=sumxbar/k
Rbar=sumR/k
xbar R
5.8 0.42
6.1 0.38
16.02 0.08
15.95 0.15
16.12 0.42
6.18 0.23
5.87 0.36
16.2 0.4
Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8
Xdoublebar=88.24/8
Xdoublebar=11.03
Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8
Rbar=2.44/8
Rbar=0.305
The lower control limit for the x-bar chart is
LCL=xdoublebar-A2(Rbar)
LCL=11.03-0.308*0.305
LCL=11.03-0.0939
LCL=10.9361
First find the length of leg BC by using the Pythagorean theorem BC=132+52=12 ft if we find the midpoint of BC which is 6 ft we find where the angle bisector would touch the BC. From there we construct another triangle ANC where AC is equal to 5 ft and NC is equal to 6 ft where we can again use the Pythagorean theorem to find the length of the hypotenuse which is the angle bisector AN=Angle Bisector=62+52<span>=7.8102 ft.</span>
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Answer:
5/8
Step-by-step explanation:
i took the test hope this helps
